Location via proxy:   [ UP ]  
[Report a bug]   [Manage cookies]                
A056757
Cube of number of divisors is larger than the number.
21
2, 3, 4, 5, 6, 7, 8, 9, 10, 12, 14, 15, 16, 18, 20, 21, 22, 24, 25, 26, 27, 28, 30, 32, 33, 34, 35, 36, 38, 39, 40, 42, 44, 45, 46, 48, 50, 51, 52, 54, 55, 56, 57, 58, 60, 62, 63, 64, 66, 68, 70, 72, 75, 76, 78, 80, 81, 84, 88, 90, 92, 96, 98, 99, 100, 102, 104, 105, 108, 110
OFFSET
1,1
COMMENTS
Sequence is finite with 51261 terms. - Charles R Greathouse IV, Apr 27 2011 [Corrected by Amiram Eldar, Jun 02 2024]
The last odd term is a(15199) = 883575. The odd terms are in A056761. - T. D. Noe, May 14 2013
LINKS
Charles R Greathouse IV, Table of n, a(n) for n = 1..51261 (complete sequence, corrected by Amiram Eldar)
FORMULA
{ k : A000005(k)^3 > k}.
EXAMPLE
k = 27935107200 = 128*27*25*7*11*13*17*19 has 3072 divisors, 3072^3/k = 1.03779..., so k is a term.
MATHEMATICA
t = {}; Do[If[n < DivisorSigma[0, n]^3, AppendTo[t, n]], {n, 10^3}]; t (* T. D. Noe, May 14 2013 *)
Select[Range[120], DivisorSigma[0, #]^3>#&] (* Harvey P. Dale, Apr 22 2019 *)
PROG
(PARI) is(n)=numdiv(n)^3>n \\ Charles R Greathouse IV, Sep 14 2015
CROSSREFS
KEYWORD
fini,full,nonn
AUTHOR
Labos Elemer, Aug 16 2000
STATUS
approved