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Zippula

From Wikipedia, the free encyclopedia
(Redirected from Zippuli)

Zippula
Place of originItaly
Region or stateCalabria
Main ingredientsFlour, potatoes

Zippula (pl.: zippuli; Italian: zeppola or zeppola calabrese) is a fried dough made to a recipe from Calabria, Italy. Zippula is made with flour, water, yeast, boiled potatoes, and a pinch of salt.[1] There are many variations: often anchovies are added, but salt cod, stockfish, cheese, sun-dried tomatoes, olives or 'nduja may also be added.[2]

Although variations exist amongst some Calabrian families, zippula dough is prepared with fresh parsley, formed into zippuli and deep-fried in a skillet.[citation needed]

They are traditional in the provinces of Reggio Calabria, Catanzaro, Vibo Valentia, and Cosenza.[citation needed]

See also

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References

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  1. ^ "Zippuli recipe". Il Globo. Retrieved 25 February 2022.
  2. ^ "Zippuli - Traditional Appetizer From Calabria". TasteAtlas. Retrieved 25 February 2022.