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Commit faccfa4

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Parth Shah
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O(n) time and O(1) space using recursion
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# Definition for a binary tree node.
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# class TreeNode:
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# def __init__(self, val=0, left=None, right=None):
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# self.val = val
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# self.left = left
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# self.right = right
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class Solution:
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def sortedArrayToBST(self, nums: List[int]) -> TreeNode:
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if not nums:
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return None
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n = len(nums)
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root = TreeNode(nums[n//2])
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root.left = self.sortedArrayToBST(nums[:n//2])
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root.right = self.sortedArrayToBST(nums[n//2+1:])
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return root

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