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add new solution
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# Trie(发音类似 "try")或者说 前缀树 是一种树形数据结构,用于高效地存储和检索字符串数据集中的键。这一数据结构有相当多的应用情景,例如自动补完和拼
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# 写检查。
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#
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# 请你实现 Trie 类:
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#
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#
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# Trie() 初始化前缀树对象。
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# void insert(String word) 向前缀树中插入字符串 word 。
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# boolean search(String word) 如果字符串 word 在前缀树中,返回 true(即,在检索之前已经插入);否则,返回 false
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# 。
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# boolean startsWith(String prefix) 如果之前已经插入的字符串 word 的前缀之一为 prefix ,返回 true ;否
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# 则,返回 false 。
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#
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#
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#
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#
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# 示例:
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#
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#
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# 输入
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# ["Trie", "insert", "search", "search", "startsWith", "insert", "search"]
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# [[], ["apple"], ["apple"], ["app"], ["app"], ["app"], ["app"]]
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# 输出
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# [null, null, true, false, true, null, true]
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#
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# 解释
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# Trie trie = new Trie();
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# trie.insert("apple");
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# trie.search("apple"); // 返回 True
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# trie.search("app"); // 返回 False
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# trie.startsWith("app"); // 返回 True
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# trie.insert("app");
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# trie.search("app"); // 返回 True
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#
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#
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#
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#
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# 提示:
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#
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#
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# 1 <= word.length, prefix.length <= 2000
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# word 和 prefix 仅由小写英文字母组成
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# insert、search 和 startsWith 调用次数 总计 不超过 3 * 104 次
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#
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# Related Topics 设计 字典树 哈希表 字符串
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# 👍 1255 👎 0
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# leetcode submit region begin(Prohibit modification and deletion)
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class TreeNode(object):
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def __init__(self, char=None):
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self.char = char
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self.is_end=False
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self.children = {}
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def insert(self, c):
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if c in self.children:
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return self.children[c]
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else:
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self.children[c] = TreeNode(c)
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return self.children[c]
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def search(self, c):
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return self.children.get(c, None)
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class Trie:
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def __init__(self):
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self.root = TreeNode()
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def insert(self, word: str) -> None:
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node = self.root
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for c in word:
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node = node.insert(c)
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node.is_end=True
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def search(self, word: str) -> bool:
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node = self.root
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for c in word:
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node = node.search(c)
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if not node:
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return False
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if node.is_end:
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return True
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else:
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return False
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def startsWith(self, prefix: str) -> bool:
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node = self.root
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for c in prefix:
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node = node.search(c)
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if not node:
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return False
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return True
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# Your Trie object will be instantiated and called as such:
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# obj = Trie()
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# obj.insert(word)
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# param_2 = obj.search(word)
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# param_3 = obj.startsWith(prefix)
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# leetcode submit region end(Prohibit modification and deletion)

script/[872]叶子相似的树.py

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@@ -55,7 +55,7 @@ def seralize(root, ans):
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return
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if not root.left and not root.right:
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ans.append(root.val)
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return ans
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return
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seralize(root.left, ans)
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seralize(root.right, ans)
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return ans

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