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| 1 | +// https://leetcode.com/problems/maximum-count-of-positive-integer-and-negative-integer |
| 2 | +// T: O(log(N)) |
| 3 | +// S: O(1) |
| 4 | + |
| 5 | +public class MaximumCountOfPositiveIntegerAndNegativeInteger { |
| 6 | + public int maximumCount(int[] nums) { |
| 7 | + int firstIndex = binarySearchFirstIndex(nums, 0); |
| 8 | + int lastIndex = binarySearchLastIndex(nums, 0); |
| 9 | + return Math.max(firstIndex, nums.length - lastIndex - (lastIndex < nums.length && nums[lastIndex] == 0 ? 1 : 0)); |
| 10 | + } |
| 11 | + |
| 12 | + // left leaning binary search with insertion point |
| 13 | + private int binarySearchFirstIndex(int[] array, int x) { |
| 14 | + int left = 0, right = array.length - 1, middle, index = -1; |
| 15 | + while (left <= right) { |
| 16 | + middle = left + (right - left) / 2; |
| 17 | + if (array[middle] == x) { |
| 18 | + index = middle; |
| 19 | + right = middle - 1; |
| 20 | + } else if (array[middle] > x) right = middle - 1; |
| 21 | + else left = middle + 1; |
| 22 | + } |
| 23 | + return index == -1 ? left : index; |
| 24 | + } |
| 25 | + |
| 26 | + // right leaning binary search with insertion point |
| 27 | + private int binarySearchLastIndex(int[] array, int x) { |
| 28 | + int left = 0, right = array.length - 1, middle, index = -1; |
| 29 | + while (left <= right) { |
| 30 | + middle = left + (right - left) / 2; |
| 31 | + if (array[middle] == x) { |
| 32 | + index = middle; |
| 33 | + left = middle + 1; |
| 34 | + } else if (array[middle] > x) right = middle - 1; |
| 35 | + else left = middle + 1; |
| 36 | + } |
| 37 | + return index == -1 ? left : index; |
| 38 | + } |
| 39 | +} |
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