Add solution #2632

Author: JoshCrozier

README.md

@@ -1974,6 +1974,7 @@
 2629|[Function Composition](./solutions/2629-function-composition.js)|Easy|
 2630|[Memoize II](./solutions/2630-memoize-ii.js)|Hard|
 2631|[Group By](./solutions/2631-group-by.js)|Medium|
+2632|[Curry](./solutions/2632-curry.js)|Medium|
 2634|[Filter Elements from Array](./solutions/2634-filter-elements-from-array.js)|Easy|
 2635|[Apply Transform Over Each Element in Array](./solutions/2635-apply-transform-over-each-element-in-array.js)|Easy|
 2636|[Promise Pool](./solutions/2636-promise-pool.js)|Medium|

solutions/2632-curry.js

@@ -0,0 +1,28 @@
+/**
+ * 2632. Curry
+ * https://leetcode.com/problems/curry/
+ * Difficulty: Medium
+ *
+ * Given a function fn, return a curried version of that function.
+ *
+ * A curried function is a function that accepts fewer or an equal number of parameters as the
+ * original function and returns either another curried function or the same value the original
+ * function would have returned.
+ *
+ * In practical terms, if you called the original function like sum(1,2,3), you would call the
+ * curried version like csum(1)(2)(3), csum(1)(2,3), csum(1,2)(3), or csum(1,2,3). All these
+ * methods of calling the curried function should return the same value as the original.
+ */
+
+/**
+ * @param {Function} fn
+ * @return {Function}
+ */
+var curry = function(fn) {
+  return function curried(...args) {
+    if (args.length >= fn.length) {
+      return fn(...args);
+    }
+    return (...nextArgs) => curried(...args, ...nextArgs);
+  };
+};