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2 | 2 |
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3 | 3 | /**198. House Robber
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4 | 4 |
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5 |
| -You are a professional robber planning to rob houses along a street. |
| 5 | + You are a professional robber planning to rob houses along a street. |
6 | 6 | Each house has a certain amount of money stashed,
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7 |
| - the only constraint stopping you from robbing each of them is that adjacent houses have security system connected and |
8 |
| - it will automatically contact the police if two adjacent houses were broken into on the same night. |
9 |
| -
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10 |
| -Given a list of non-negative integers representing the amount of money of each house, |
| 7 | + the only constraint stopping you from robbing each of them is that adjacent houses have security |
| 8 | + system connected and it will automatically contact the police if two adjacent houses were broken into on the same night. |
| 9 | + Given a list of non-negative integers representing the amount of money of each house, |
11 | 10 | determine the maximum amount of money you can rob tonight without alerting the police.
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| 11 | +
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| 12 | + Example 1: |
| 13 | + Input: [1,2,3,1] |
| 14 | + Output: 4 |
| 15 | + Explanation: Rob house 1 (money = 1) and then rob house 3 (money = 3). |
| 16 | + Total amount you can rob = 1 + 3 = 4. |
| 17 | +
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| 18 | + Example 2: |
| 19 | + Input: [2,7,9,3,1] |
| 20 | + Output: 12 |
| 21 | + Explanation: Rob house 1 (money = 2), rob house 3 (money = 9) and rob house 5 (money = 1). |
| 22 | + Total amount you can rob = 2 + 9 + 1 = 12. |
12 | 23 | */
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13 | 24 | public class _198 {
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14 | 25 |
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15 |
| - public int rob(int[] nums) { |
16 |
| - if (nums == null || nums.length == 0) { |
17 |
| - return 0; |
18 |
| - } |
19 |
| - if (nums.length == 1) { |
20 |
| - return nums[0]; |
| 26 | + public static class Solution1 { |
| 27 | + public int rob(int[] nums) { |
| 28 | + if (nums == null || nums.length == 0) { |
| 29 | + return 0; |
| 30 | + } |
| 31 | + if (nums.length == 1) { |
| 32 | + return nums[0]; |
| 33 | + } |
| 34 | + if (nums.length == 2) { |
| 35 | + return Math.max(nums[0], nums[1]); |
| 36 | + } |
| 37 | + int[] dp = new int[nums.length]; |
| 38 | + dp[0] = nums[0]; |
| 39 | + dp[1] = Math.max(nums[0], nums[1]); |
| 40 | + for (int i = 2; i < nums.length; i++) { |
| 41 | + dp[i] = Math.max(dp[i - 2] + nums[i], dp[i - 1]); |
| 42 | + } |
| 43 | + return dp[nums.length - 1]; |
21 | 44 | }
|
22 |
| - if (nums.length == 2) { |
23 |
| - return Math.max(nums[0], nums[1]); |
24 |
| - } |
25 |
| - int[] dp = new int[nums.length]; |
26 |
| - dp[0] = nums[0]; |
27 |
| - dp[1] = Math.max(nums[0], nums[1]); |
28 |
| - for (int i = 2; i < nums.length; i++) { |
29 |
| - dp[i] = Math.max(dp[i - 2] + nums[i], dp[i - 1]); |
30 |
| - } |
31 |
| - return dp[nums.length - 1]; |
32 | 45 | }
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33 |
| - |
34 | 46 | }
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