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更新 面试题02.07.链表相交 错别字勘误
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problems/面试题02.07.链表相交.md

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![面试题02.07.链表相交_2](https://code-thinking.cdn.bcebos.com/pics/面试题02.07.链表相交_2.png)
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此时我们就可以比较curA和curB是否相同,如果不相同,同时向后移动curA和curB,如果遇到curA == curB,则找到焦点
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此时我们就可以比较curA和curB是否相同,如果不相同,同时向后移动curA和curB,如果遇到curA == curB,则找到交点
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否则循环退出返回空指针。
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