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2 | 2 |
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3 | 3 | import com.fishercoder.common.classes.TreeNode;
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4 | 4 |
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| 5 | +import java.util.HashMap; |
| 6 | +import java.util.Map; |
| 7 | + |
5 | 8 | /**
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| 9 | + * 124. Binary Tree Maximum Path Sum |
6 | 10 | * Given a binary tree, find the maximum path sum.
|
7 |
| -
|
8 |
| - For this problem, a path is defined as any sequence of nodes from some starting node to any node |
9 |
| - in the tree along the parent-child connections. |
| 11 | + * For this problem, a path is defined as any sequence of nodes from some starting node to any node |
| 12 | + * in the tree along the parent-child connections. |
10 | 13 |
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11 | 14 | The path must contain at least one node and does not need to go through the root.
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12 | 15 |
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|
21 | 24 | */
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22 | 25 | public class _124 {
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23 | 26 |
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24 |
| - int max = Integer.MIN_VALUE; |
25 |
| - |
26 |
| - public int maxPathSum(TreeNode root) { |
27 |
| - dfs(root); |
28 |
| - return max; |
29 |
| - } |
| 27 | + public static class Solution1 { |
| 28 | + int max = Integer.MIN_VALUE; |
30 | 29 |
|
31 |
| - private int dfs(TreeNode root) { |
32 |
| - if (root == null) { |
33 |
| - return 0; |
| 30 | + public int maxPathSum(TreeNode root) { |
| 31 | + dfs(root); |
| 32 | + return max; |
34 | 33 | }
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35 | 34 |
|
36 |
| - int left = Math.max(dfs(root.left), 0); |
37 |
| - int right = Math.max(dfs(root.right), 0); |
| 35 | + private int dfs(TreeNode root) { |
| 36 | + if (root == null) { |
| 37 | + return 0; |
| 38 | + } |
| 39 | + |
| 40 | + int left = Math.max(dfs(root.left), 0); |
| 41 | + int right = Math.max(dfs(root.right), 0); |
38 | 42 |
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39 |
| - max = Math.max(max, root.val + left + right); |
| 43 | + max = Math.max(max, root.val + left + right); |
40 | 44 |
|
41 |
| - return root.val + Math.max(left, right); |
| 45 | + return root.val + Math.max(left, right); |
| 46 | + } |
42 | 47 | }
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43 | 48 |
|
| 49 | + public static class Solution2 { |
| 50 | + /**This one uses a map to cache, but surprisingly, it's 10% slower than all submissions compared with solution1*/ |
| 51 | + int max = Integer.MIN_VALUE; |
| 52 | + |
| 53 | + public int maxPathSum(TreeNode root) { |
| 54 | + Map<TreeNode, Integer> map = new HashMap<>(); |
| 55 | + dfs(root, map); |
| 56 | + return max; |
| 57 | + } |
| 58 | + |
| 59 | + private int dfs(TreeNode root, Map<TreeNode, Integer> map) { |
| 60 | + if (root == null) { |
| 61 | + return 0; |
| 62 | + } |
| 63 | + if (map.containsKey(root)) { |
| 64 | + return map.get(root); |
| 65 | + } |
| 66 | + int left = Math.max(0, dfs(root.left, map)); |
| 67 | + int right = Math.max(0, dfs(root.right, map)); |
| 68 | + max = Math.max(max, root.val + left + right); |
| 69 | + int pathSum = root.val + Math.max(left, right); |
| 70 | + map.put(root, pathSum); |
| 71 | + return pathSum; |
| 72 | + } |
| 73 | + } |
44 | 74 | }
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