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index.ts
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/**
* # 17. Letter Combinations of a Phone Number
*
* Given a string containing digits from 2-9 inclusive,
* return all possible letter combinations that the number could represent.
*
* A mapping of digit to letters (just like on the telephone buttons)
* is given below. Note that 1 does not map to any letters.
*
* 
*
* ## Example
*
* ```bash
* Input: "23"
* Output: ["ad", "ae", "af", "bd", "be", "bf", "cd", "ce", "cf"].
* ```
*
* ## Note
*
* Although the above answer is in lexicographical order, your answer could be in any order you want.
*
* ## Thinking
*
* 笛卡尔积有很多应用场景:
*
* 1. 输入法简拼,快捷打字
* 2. 电商规格项规格值算 SKU
* 3. 商品详情页面下单时勾选规格值,根据 SKU 库存排除无货的规格值可选
* 4. 电商营销场景组合优惠券场景
*/
export type Solution = (digits: string) => string[];
/**
* 笛卡尔积
* @date 2020.06.28 12:10
* @time
* @space
* @runtime 100 ms, faster than 100.00%
* @memory 33.1 Mb, less than 100.00%
* @runtime_cn 72 ms, faster than 31.25%
* @memory_cn 32.4 MB, less than 100.00%
*/
export const letterCombinations = (digits: string): string[] => {
if (digits === "") {
return [];
}
// the phone keypad
const keypad: { [k: string]: string[] } = {
"2": ["a", "b", "c"],
"3": ["d", "e", "f"],
"4": ["g", "h", "i"],
"5": ["j", "k", "l"],
"6": ["m", "n", "o"],
"7": ["p", "q", "r", "s"],
"8": ["t", "u", "v"],
"9": ["w", "x", "y", "z"],
};
const s = digits.split("").map((d) => keypad[d]);
const result: string[] = [];
const stack: string[] = [];
let point = 0;
const loop = () => {
for (let i = 0, array = s[point++]; i < array.length; i++) {
stack.push(array[i]);
if (point == digits.length) {
result.push(stack.join(""));
} else {
loop();
point--;
}
stack.pop();
}
};
loop();
return result;
};