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| 1 | +#include <stdio.h> |
| 2 | +#include <stdlib.h> |
| 3 | +#include <stdbool.h> |
| 4 | + |
| 5 | +struct TreeNode { |
| 6 | + int val; |
| 7 | + struct TreeNode *left; |
| 8 | + struct TreeNode *right; |
| 9 | +}; |
| 10 | + |
| 11 | +struct ListNode { |
| 12 | + int val; |
| 13 | + struct ListNode *next; |
| 14 | +}; |
| 15 | + |
| 16 | +struct BSTIterator { |
| 17 | + struct ListNode dummy; |
| 18 | + struct ListNode *p; |
| 19 | +}; |
| 20 | + |
| 21 | +static void bst_iter_generater(struct TreeNode *node, struct BSTIterator *iter) |
| 22 | +{ |
| 23 | + if (node->left != NULL) { |
| 24 | + bst_iter_generater(node->left, iter); |
| 25 | + } |
| 26 | + |
| 27 | + struct ListNode *new = malloc(sizeof(*new)); |
| 28 | + new->val = node->val; |
| 29 | + new->next = NULL; |
| 30 | + if (iter->p != NULL) { |
| 31 | + iter->p->next = new; |
| 32 | + } else { |
| 33 | + iter->dummy.next = new; |
| 34 | + } |
| 35 | + iter->p = new; |
| 36 | + |
| 37 | + if (node->right != NULL) { |
| 38 | + bst_iter_generater(node->right, iter); |
| 39 | + } |
| 40 | +} |
| 41 | + |
| 42 | +static struct BSTIterator *bstIteratorCreate(struct TreeNode *root) |
| 43 | +{ |
| 44 | + struct BSTIterator *iter = malloc(sizeof(*iter)); |
| 45 | + if (root != NULL) { |
| 46 | + iter->p = NULL; |
| 47 | + bst_iter_generater(root, iter); |
| 48 | + } |
| 49 | + iter->p = &iter->dummy; |
| 50 | + return iter; |
| 51 | +} |
| 52 | + |
| 53 | +/** @return whether we have a next smallest number */ |
| 54 | +static bool bstIteratorHasNext(struct BSTIterator *iter) |
| 55 | +{ |
| 56 | + return iter->p->next != NULL; |
| 57 | +} |
| 58 | + |
| 59 | +/** @return the next smallest number */ |
| 60 | +static int bstIteratorNext(struct BSTIterator *iter) |
| 61 | +{ |
| 62 | + iter->p = iter->p->next; |
| 63 | + return iter->p->val; |
| 64 | +} |
| 65 | + |
| 66 | +/** Deallocates memory iteriously allocated for the iterator */ |
| 67 | +static void bstIteratorFree(struct BSTIterator *iter) |
| 68 | +{ |
| 69 | + iter->p = iter->dummy.next; |
| 70 | + while (iter->p != NULL) { |
| 71 | + iter->dummy.next = iter->p->next; |
| 72 | + free(iter->p); |
| 73 | + iter->p = iter->dummy.next; |
| 74 | + } |
| 75 | +} |
| 76 | + |
| 77 | +int main(void) |
| 78 | +{ |
| 79 | +#if 1 |
| 80 | + struct TreeNode root; |
| 81 | + root.val = 7; |
| 82 | + |
| 83 | + struct TreeNode node1[2]; |
| 84 | + node1[0].val = 3; |
| 85 | + node1[1].val = 15; |
| 86 | + |
| 87 | + struct TreeNode node2[4]; |
| 88 | + node2[2].val = 9; |
| 89 | + node2[3].val = 20; |
| 90 | + |
| 91 | + root.left = &node1[0]; |
| 92 | + root.right = &node1[1]; |
| 93 | + |
| 94 | + node1[0].left = NULL; |
| 95 | + node1[0].right = NULL; |
| 96 | + node1[1].left = &node2[2]; |
| 97 | + node1[1].right = &node2[3]; |
| 98 | +#else |
| 99 | + struct TreeNode root; |
| 100 | + root.val = 1; |
| 101 | + |
| 102 | + struct TreeNode node1[2]; |
| 103 | + node1[0].val = 2; |
| 104 | + node1[1].val = 3; |
| 105 | + |
| 106 | + struct TreeNode node2[4]; |
| 107 | + node2[0].val = 4; |
| 108 | + node2[3].val = 5; |
| 109 | + |
| 110 | + root.left = &node1[0]; |
| 111 | + root.right = &node1[1]; |
| 112 | + |
| 113 | + node1[0].left = &node2[0]; |
| 114 | + node1[0].right = NULL; |
| 115 | + node1[1].left = NULL; |
| 116 | + node1[1].right = &node2[3]; |
| 117 | +#endif |
| 118 | + |
| 119 | + node2[0].left = NULL; |
| 120 | + node2[0].right = NULL; |
| 121 | + node2[1].left = NULL; |
| 122 | + node2[1].right = NULL; |
| 123 | + node2[2].left = NULL; |
| 124 | + node2[2].right = NULL; |
| 125 | + node2[3].left = NULL; |
| 126 | + node2[3].right = NULL; |
| 127 | + |
| 128 | + struct BSTIterator *i = bstIteratorCreate(&root); |
| 129 | + while (bstIteratorHasNext(i)) { |
| 130 | + printf("%d\n", bstIteratorNext(i)); |
| 131 | + } |
| 132 | + bstIteratorFree(i); |
| 133 | + return 0; |
| 134 | +} |
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