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Add solution #707
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0707-design-linked-list.js

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/**
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* 707. Design Linked List
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* https://leetcode.com/problems/design-linked-list/
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* Difficulty: Medium
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*
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* Design your implementation of the linked list. You can choose to use a singly or
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* doubly linked list.
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*
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* A node in a singly linked list should have two attributes: val and next. val is the value
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* of the current node, and next is a pointer/reference to the next node.
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*
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* If you want to use the doubly linked list, you will need one more attribute prev to indicate
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* the previous node in the linked list. Assume all nodes in the linked list are 0-indexed.
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*
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* Implement the MyLinkedList class:
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* - MyLinkedList() Initializes the MyLinkedList object.
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* - int get(int index) Get the value of the indexth node in the linked list. If the
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* index is invalid, return -1.
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* - void addAtHead(int val) Add a node of value val before the first element of the
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* linked list. After the insertion, the new node will be the first node of the linked list.
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* - void addAtTail(int val) Append a node of value val as the last element of the linked list.
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* - void addAtIndex(int index, int val) Add a node of value val before the indexth node
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* in the linked list. If index equals the length of the linked list, the node will be
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* appended to the end of the linked list. If index is greater than the length, the node
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* will not be inserted.
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* - void deleteAtIndex(int index) Delete the indexth node in the linked list, if the index
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* is valid.
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*/
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var MyLinkedList = function() {
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this.head = null;
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this.size = 0;
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};
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/**
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* @param {number} index
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* @return {number}
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*/
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MyLinkedList.prototype.get = function(index) {
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if (index < 0 || index >= this.size) return -1;
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let current = this.head;
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while (index--) current = current.next;
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return current.val;
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};
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/**
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* @param {number} val
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* @return {void}
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*/
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MyLinkedList.prototype.addAtHead = function(val) {
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const node = new Node(val);
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node.next = this.head;
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this.head = node;
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this.size++;
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};
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/**
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* @param {number} val
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* @return {void}
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*/
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MyLinkedList.prototype.addAtTail = function(val) {
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const node = new Node(val);
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if (!this.head) {
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this.head = node;
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} else {
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let current = this.head;
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while (current.next) current = current.next;
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current.next = node;
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}
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this.size++;
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};
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/**
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* @param {number} index
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* @param {number} val
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* @return {void}
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*/
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MyLinkedList.prototype.addAtIndex = function(index, val) {
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if (index < 0 || index > this.size) return;
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if (index === 0) return this.addAtHead(val);
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const node = new Node(val);
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let current = this.head;
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while (--index) current = current.next;
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node.next = current.next;
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current.next = node;
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this.size++;
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};
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/**
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* @param {number} index
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* @return {void}
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*/
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MyLinkedList.prototype.deleteAtIndex = function(index) {
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if (index < 0 || index >= this.size) return;
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this.size--;
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if (index === 0) {
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this.head = this.head.next;
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return;
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}
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let current = this.head;
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while (--index) current = current.next;
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current.next = current.next.next;
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};
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class Node {
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constructor(val) {
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this.val = val;
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this.next = null;
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}
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}

README.md

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704|[Binary Search](./0704-binary-search.js)|Easy|
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705|[Design HashSet](./0705-design-hashset.js)|Easy|
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706|[Design HashMap](./0706-design-hashmap.js)|Easy|
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707|[Design Linked List](./0707-design-linked-list.js)|Medium|
538539
713|[Subarray Product Less Than K](./0713-subarray-product-less-than-k.js)|Medium|
539540
714|[Best Time to Buy and Sell Stock with Transaction Fee](./0714-best-time-to-buy-and-sell-stock-with-transaction-fee.js)|Medium|
540541
717|[1-bit and 2-bit Characters](./0717-1-bit-and-2-bit-characters.js)|Easy|

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