Add solution #2606

Author: JoshCrozier

README.md

@@ -1939,6 +1939,7 @@
 2600|[K Items With the Maximum Sum](./solutions/2600-k-items-with-the-maximum-sum.js)|Easy|
 2601|[Prime Subtraction Operation](./solutions/2601-prime-subtraction-operation.js)|Medium|
 2605|[Form Smallest Number From Two Digit Arrays](./solutions/2605-form-smallest-number-from-two-digit-arrays.js)|Easy|
+2606|[Find the Substring With Maximum Cost](./solutions/2606-find-the-substring-with-maximum-cost.js)|Medium|
 2615|[Sum of Distances](./solutions/2615-sum-of-distances.js)|Medium|
 2618|[Check if Object Instance of Class](./solutions/2618-check-if-object-instance-of-class.js)|Medium|
 2619|[Array Prototype Last](./solutions/2619-array-prototype-last.js)|Easy|

solutions/2606-find-the-substring-with-maximum-cost.js

@@ -0,0 +1,42 @@
+/**
+ * 2606. Find the Substring With Maximum Cost
+ * https://leetcode.com/problems/find-the-substring-with-maximum-cost/
+ * Difficulty: Medium
+ *
+ * You are given a string s, a string chars of distinct characters and an integer array vals of
+ * the same length as chars.
+ *
+ * The cost of the substring is the sum of the values of each character in the substring. The
+ * cost of an empty string is considered 0.
+ *
+ * The value of the character is defined in the following way:
+ * - If the character is not in the string chars, then its value is its corresponding position
+ *   (1-indexed) in the alphabet.
+ *   - For example, the value of 'a' is 1, the value of 'b' is 2, and so on. The value of 'z' is 26.
+ * - Otherwise, assuming i is the index where the character occurs in the string chars, then its
+ *   value is vals[i].
+ *
+ * Return the maximum cost among all substrings of the string s.
+ */
+
+/**
+ * @param {string} s
+ * @param {string} chars
+ * @param {number[]} vals
+ * @return {number}
+ */
+var maximumCostSubstring = function(s, chars, vals) {
+  const charValues = new Array(26).fill().map((_, i) => i + 1);
+  for (let i = 0; i < chars.length; i++) {
+    charValues[chars.charCodeAt(i) - 97] = vals[i];
+  }
+
+  let result = 0;
+  let currentCost = 0;
+  for (const char of s) {
+    currentCost = Math.max(0, currentCost + charValues[char.charCodeAt(0) - 97]);
+    result = Math.max(result, currentCost);
+  }
+
+  return result;
+};