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CheckValidityBST Solution uploaded!
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# Definition for a binary tree node.
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# class TreeNode:
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# def __init__(self, val=0, left=None, right=None):
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# self.val = val
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# self.left = left
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# self.right = right
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class Solution:
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def isValidBST(self, root: Optional[TreeNode]) -> bool:
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# Time: O(n)
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def valid(node, left, right):
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if not node:
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return True
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if not (node.val < right and node.val > left):
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return False
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return (valid(node.left, left, node.val) and
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valid(node.right, node.val, right))
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return valid(root, float("-inf"), float("inf"))
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