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| 1 | +/** |
| 2 | + * [155] Min Stack |
| 3 | + * |
| 4 | + * |
| 5 | + * Design a stack that supports push, pop, top, and retrieving the minimum element in constant time. |
| 6 | + * |
| 7 | + * |
| 8 | + * push(x) -- Push element x onto stack. |
| 9 | + * |
| 10 | + * |
| 11 | + * pop() -- Removes the element on top of the stack. |
| 12 | + * |
| 13 | + * |
| 14 | + * top() -- Get the top element. |
| 15 | + * |
| 16 | + * |
| 17 | + * getMin() -- Retrieve the minimum element in the stack. |
| 18 | + * |
| 19 | + * |
| 20 | + * |
| 21 | + * |
| 22 | + * Example:<br /> |
| 23 | + * |
| 24 | + * MinStack minStack = new MinStack(); |
| 25 | + * minStack.push(-2); |
| 26 | + * minStack.push(0); |
| 27 | + * minStack.push(-3); |
| 28 | + * minStack.getMin(); --> Returns -3. |
| 29 | + * minStack.pop(); |
| 30 | + * minStack.top(); --> Returns 0. |
| 31 | + * minStack.getMin(); --> Returns -2. |
| 32 | + * |
| 33 | + * |
| 34 | + */ |
| 35 | +pub struct Solution {} |
| 36 | + |
| 37 | +// submission codes start here |
| 38 | + |
| 39 | +/* |
| 40 | + 这题居然是 easy... 我怀疑人生了, getMin() 怎么能做到常数时间? Heap 也是 LogN 啊 |
| 41 | +
|
| 42 | + 看了最高票解之后...........天哪, 我可太菜了 |
| 43 | +
|
| 44 | + 核心思想是保证每次 pop 时都能以常数时间更新最小值, 这就需要在空间上以某种方式记录下来 |
| 45 | +
|
| 46 | + 那一种做法就是存储每个元素和最小值之间的差值, 这样 pop 的时候就能不断还原出原始值 |
| 47 | +
|
| 48 | + 另一种更直观的做法就是每次入栈 min 时, 都把前一个 min (当前第二小的数字) 放在它前面, 作为记录 |
| 49 | + */ |
| 50 | +struct MinStack { |
| 51 | + vec: Vec<i32>, |
| 52 | + min: i32, |
| 53 | +} |
| 54 | + |
| 55 | +impl MinStack { |
| 56 | + |
| 57 | + /** initialize your data structure here. */ |
| 58 | + pub fn new() -> Self { |
| 59 | + MinStack{ |
| 60 | + vec: Vec::new(), |
| 61 | + min: i32::max_value(), |
| 62 | + } |
| 63 | + } |
| 64 | + |
| 65 | + pub fn push(&mut self, x: i32) { |
| 66 | + if x <= self.min { |
| 67 | + self.vec.push(self.min); |
| 68 | + self.min = x; |
| 69 | + } |
| 70 | + self.vec.push(x); |
| 71 | + } |
| 72 | + |
| 73 | + pub fn pop(&mut self) { |
| 74 | + if self.vec.pop().unwrap() == self.min { |
| 75 | + self.min = self.vec.pop().unwrap(); |
| 76 | + } |
| 77 | + } |
| 78 | + |
| 79 | + pub fn top(&self) -> i32 { |
| 80 | + *self.vec.last().unwrap() |
| 81 | + } |
| 82 | + |
| 83 | + pub fn get_min(&self) -> i32 { |
| 84 | + self.min |
| 85 | + } |
| 86 | +} |
| 87 | + |
| 88 | +/** |
| 89 | + * Your MinStack object will be instantiated and called as such: |
| 90 | + * let obj = MinStack::new(); |
| 91 | + * obj.push(x); |
| 92 | + * obj.pop(); |
| 93 | + * let ret_3: i32 = obj.top(); |
| 94 | + * let ret_4: i32 = obj.get_min(); |
| 95 | + */ |
| 96 | + |
| 97 | +// submission codes end |
| 98 | + |
| 99 | +#[cfg(test)] |
| 100 | +mod tests { |
| 101 | + use super::*; |
| 102 | + |
| 103 | + #[test] |
| 104 | + pub fn test_155() { |
| 105 | + let mut min_stack = MinStack::new(); |
| 106 | + min_stack.push(-2); |
| 107 | + min_stack.push(0); |
| 108 | + min_stack.push(-3); |
| 109 | + assert_eq!(min_stack.get_min(), -3); // --> Returns -3. |
| 110 | + min_stack.pop(); |
| 111 | + assert_eq!(min_stack.top(), 0); // --> Returns 0. |
| 112 | + assert_eq!(min_stack.get_min(), -2); // --> Returns -2.[] |
| 113 | + } |
| 114 | +} |
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