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a(n) = n^(n+1) + (n-1)^2.
1

%I #16 Sep 08 2022 08:44:50

%S 1,1,9,85,1033,15641,279961,5764837,134217777,3486784465,100000000081,

%T 3138428376821,106993205379193,3937376385699433,155568095557812393,

%U 6568408355712890821,295147905179352826081,14063084452067724991265,708235345355337676357921

%N a(n) = n^(n+1) + (n-1)^2.

%H Vincenzo Librandi, <a href="/A029711/b029711.txt">Table of n, a(n) for n = 0..200</a>

%H J. S. Tanton, <a href="http://www.themathcircle.org/researchproblems.php">A collection of research problems</a>

%t Table[n^(n+1)+(n-1)^2,{n,0,30}] (* _Harvey P. Dale_, May 07 2016 *)

%o (Magma) [n^(n+1)+(n-1)^2: n in [0..20]]; // _Vincenzo Librandi_, May 08 2016

%K nonn

%O 0,3

%A _N. J. A. Sloane_, Apr 13 2003