OFFSET
0,2
COMMENTS
LINKS
Harvey P. Dale, Table of n, a(n) for n = 0..13
FORMULA
a(2n) = 6*[10^{2^(n)} - 1]/9 a(2n+1) = [10^(2^n) - 1]/9
MATHEMATICA
With[{nn=5}, Join[Table[FromDigits[PadRight[{}, 2^n, 1]], {n, 0, nn}], Table[FromDigits[PadRight[{}, 2^n, 6]], {n, 0, nn}]]]//Sort (* Harvey P. Dale, Jan 23 2025 *)
CROSSREFS
KEYWORD
base,nonn,changed
AUTHOR
Amarnath Murthy, May 08 2001
EXTENSIONS
More terms from Larry Reeves (larryr(AT)acm.org), May 11 2001
STATUS
approved