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A067864
Numbers k such that k divides the sum of digits of 6^k.
7
1, 3, 9, 18, 90
OFFSET
1,2
COMMENTS
Conjecture: the sequence is finite, since (sum of the digits of 6^k)/k -> log_10(6)*4.5 ~ 3.50168 as k->infinity (this is also a conjecture). - Robert Gerbicz, May 08 2008
Next term, if it exists, exceeds 100000. - Sean A. Irvine, Apr 05 2010
EXAMPLE
a(1)=3, so 3 divides the sum of digits of 6^3 (i.e., 2 + 1 + 6 = 9).
CROSSREFS
KEYWORD
hard,nonn,base
AUTHOR
STATUS
approved