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A077399
Triangular numbers that are 1/7 of triangular numbers.
12
0, 3, 15, 780, 3828, 198135, 972315, 50325528, 246964200, 12782485995, 62727934503, 3246701117220, 15932648399580, 824649301287903, 4046829965558835, 209457675826010160, 1027878878603544528, 53201425010505292755, 261077188335334751295, 13512952494992518349628
OFFSET
0,2
FORMULA
Let b(n) be A077398(n) then a(n) = b(n)*(b(n)+1)/2.
G.f.: -3*x*(x^2+4*x+1) / ((x-1)*(x^2-16*x+1)*(x^2+16*x+1)). - Colin Barker, Jul 02 2013
Comment from _Vladimir Pletser, Feb 21 2021: (Start)
a(n) = 254 a(n - 2) - a (n - 4) + 18.
a(n) = a(n - 1) + 254 (a(n - 2) - a(n - 3)) - (a (n - 4) - a(n - 5)). (End)
MAPLE
f := gfun:-rectoproc({a(-2) = 3, a(-1) = 0, a(0) = 0, a(1) = 3, a(n) = 254*a(n-2)-a(n-4)+18}, a(n), remember); map(f, [`$`(0 .. 1000)])[] #Vladimir Pletser, Feb 21 2021
MATHEMATICA
Select[Accumulate[Range[0, 5700000]], IntegerQ[(Sqrt[56#+1]-1)/2]&] (* Harvey P. Dale, Jan 18 2013 *)
LinearRecurrence[{1, 254, -254, -1, 1}, {0, 3, 15, 780, 3828}, 30] (* G. C. Greubel, Jan 18 2018 *)
PROG
(PARI) concat(0, Vec(-3*x*(x^2+4*x+1)/((x-1)*(x^2-16*x+1)*(x^2+16*x+1)) + O(x^100))) \\ Colin Barker, May 15 2015
(Magma) Q:=Rationals(); R<x>:=PowerSeriesRing(Q, 30); [0] cat Coefficients(R!(-3*x*(x^2+4*x+1)/((x-1)*(x^2-16*x+1)*(x^2+16*x+1)))); // G. C. Greubel, Jan 18 2018
CROSSREFS
KEYWORD
easy,nonn
AUTHOR
Bruce Corrigan (scentman(AT)myfamily.com), Nov 05 2002
STATUS
approved