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Sum of all prime factors of (prime(n)+1)*(prime(n+1)+1)/4.
4

%I #11 Nov 21 2013 12:47:57

%S 3,5,7,9,12,13,13,14,15,16,27,29,23,22,18,19,41,50,29,47,48,23,23,25,

%T 34,37,28,27,38,34,28,42,40,27,36,102,122,57,46,45,33,33,110,114,31,

%U 69,70,39,52,47,33,36,37,61,64,32,37,162,189,123,90,37,40,177,213,141,111,60

%N Sum of all prime factors of (prime(n)+1)*(prime(n+1)+1)/4.

%C a(n)=A001414(A079079(n)).

%H Reinhard Zumkeller, <a href="/A079091/b079091.txt">Table of n, a(n) for n = 1..10000</a>

%t Total[Times@@@FactorInteger[#]]&/@(Times@@(#+1)/4&/@Partition[ Prime[Range[100]],2,1]) (* _Harvey P. Dale_, May 26 2011 *)

%o (Haskell)

%o a079091 = a001414 . a079079 -- _Reinhard Zumkeller_, Oct 09 2012

%Y Cf. A079090, A079089, A079086.

%K nonn

%O 1,1

%A _Reinhard Zumkeller_, Dec 22 2002