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A084178
Inverse binomial transform of Fibonacci oblongs.
2
0, 1, 0, 3, -1, 10, -7, 35, -36, 127, -165, 474, -715, 1807, -3004, 6995, -12393, 27370, -50559, 107883, -204820, 427351, -826045, 1698458, -3321891, 6765175, -13333932, 26985675, -53457121, 107746282, -214146295, 430470899, -857417220, 1720537327, -3431847189
OFFSET
0,4
COMMENTS
Inverse binomial transform of A001654.
FORMULA
a(n)=((1/2+sqrt(5)/2)^(n+1)+(1/2-sqrt(5)/2)^(n+1)-(-2)^n)/5;
G.f.: x(1+x)/(1+x-3x^2-2x^3)=x(1-x)/((1+2x)(1-x-x^2)).
a(n) = A084179(n)+A084179(n-1). - R. J. Mathar, Dec 10 2014
MATHEMATICA
LinearRecurrence[{-1, 3, 2}, {0, 1, 0}, 40] (* Harvey P. Dale, Nov 24 2020 *)
CROSSREFS
KEYWORD
easy,sign
AUTHOR
Paul Barry, May 18 2003
STATUS
approved