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A101115
Beginning with the n-th prime, the number of successive times a new prime can be formed by prepending the smallest nonzero digit.
5
0, 5, 0, 9, 5, 4, 8, 4, 5, 9, 4, 6, 2, 7, 6, 8, 9, 7, 6, 3, 14, 5, 5, 2, 4, 10, 1, 5, 7, 3, 4, 3, 5, 5, 0, 6, 5, 8, 5, 13, 4, 5, 4, 5, 3, 8, 4, 4, 5, 8, 3, 6, 1, 4, 4, 2, 5, 2, 2, 3, 4, 9, 8, 7, 4, 7, 3, 3, 5, 5, 7, 8, 4, 3, 3, 2, 1, 7, 0, 4, 3, 5, 3, 7, 9, 6, 6, 5, 6, 8
OFFSET
1,2
COMMENTS
It is possible the procedure described would generate some left-truncatable primes (A024785). Although zero digits cannot be added, it is possible the starting prime may contain zeros. Therefore the possible number of digit additions is not limited by the length of the largest known left-truncatable prime. Further, because the smallest digit that satisfies the requirement is used each time, it is possible that choosing a larger digit would allow more single digits to be added. Therefore although some of the set of left-truncatable primes may be generated by this practice, not all of them will.
In principle it is possible that some a(n) is undefined because the process could go on indefinitely, but this is very unlikely. The largest a(n) for n <= 300000 is a(49120) = 18. - Robert Israel, Jun 29 2015
LINKS
I. O. Angell, and H. J. Godwin, On Truncatable Primes, Math. Comput. 31, 265-267, 1977.
EXAMPLE
a(2) is 5 because the second prime is 3, to which single nonzero digits can be prepended 5 times yielding a new prime each time (giving preference to the smallest digit that satisfies the requirement): 13, 113, 2113, 12113, 612113 (see A053583). There is no nonzero digit which can be prepended to 612113 to yield a new prime.
a(21) = 14 because the 21st prime (73) can be prepended with single nonzero digits 14 times yielding a new prime each time: 73, 173, 6173, 66173, ..., 4818372912366173.
MAPLE
f:= proc(n) local p, nd, d, count, x, success;
p:= ithprime(n); nd:= ilog10(p);
for count from 0 do
nd:= nd+1;
success:= false;
for d from 1 to 9 do
x:= 10^nd * d + p;
if isprime(x) then
success:= true;
break
fi
od;
if not success then return(count) fi;
p:= x;
od
end proc:
map(f, [$1..100]); # Robert Israel, Jun 29 2015
PROG
(Python)
from sympy import isprime, prime
def a(n):
pn = prime(n)
s, c, found = str(pn), 0, True
while found:
found = False
for d in "123456789":
if isprime(int(d+s)):
s, c, found = d+s, c+1, True
break
return c
print([a(n) for n in range(1, 91)]) # Michael S. Branicky, Jun 24 2022
CROSSREFS
KEYWORD
base,nonn
AUTHOR
Chuck Seggelin (seqfan(AT)plastereddragon.com), Dec 02 2004
STATUS
approved