A110216 - OEIS

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A110216

Total number of coverings of a cubic board with the minimal number of knights.

1, 1, 12, 156, 888

(list; graph; refs; listen; history; text; internal format)

OFFSET

1,3

LINKS

Table of n, a(n) for n=1..5.

FORMULA

Sequence A110214 gives minimal number of knights needed to cover an n X n X n board. This sequence gives total number of solutions using A110214(n) knights.

EXAMPLE

a(3) = 12, since reflections or rotations of

OOO KKK OOO

OKO OKO OKO

OOO OOO OOO generate twelve different coverings.

CROSSREFS

This sequence is a 3-dimensional analog of A103315. a(n) = A110219(n, n, n). A102215 gives the number of inequivalent solutions.

Sequence in context: A005723 A097259 A158546 * A218839 A036276 A003130

Adjacent sequences: A110213 A110214 A110215 * A110217 A110218 A110219

KEYWORD

hard,nonn

AUTHOR

Nikolaus Meyberg (Nikolaus.Meyberg(AT)t-online.de), Jul 17 2005

STATUS

approved