%I #4 Feb 18 2022 22:27:11

%S 1,0,1,1,0,1,0,0,0,1,3,0,0,0,1,0,1,0,0,0,1,5,0,0,0,0,0,1,0,0,0,0,0,0,

%T 0,1,0,0,1,0,0,0,0,0,1,0,3,0,0,0,0,0,0,0,1

%N A054525 * A129691(unsigned).

%C Row sums = A070777: (1, 1, 2, 1, 4, 2, 6, 1, 2, 4, ...). A129691 = the unsigned inverse of A054523.

%F Moebius transform of A129691

%e First few rows of the triangle:

%e 1;

%e 0, 1;

%e 1, 0, 1;

%e 0, 0, 0, 1;

%e 3, 0, 0, 0, 1;

%e 0, 1, 0, 0, 0, 1;

%e 5, 0, 0, 0, 0, 0, 1;

%e 0, 0, 0, 0, 0, 0, 0, 1;

%e 0, 0, 1, 0, 0, 0, 0, 0, 1;

%e ...

%Y Cf. A054525, A129691, A070777, A054523.

%K nonn,tabl

%O 1,11

%A _Gary W. Adamson_, Apr 29 2007