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a(n) = ((2n+1)!)^(n+2).
5

%I #9 Apr 10 2024 13:12:10

%S 1,216,207360000,3252016064102400000,

%T 2283380023591730815784976384000000,

%U 161469323688736156802100136913438716723200000000000000,2260697901194635682690248130915498742378267539496871953338204160000000000000000

%N a(n) = ((2n+1)!)^(n+2).

%F a(n) ~ 2^(2*(n+1)*(n+2)) * exp(13/24 - 2*n*(n+2)) * n^((n+2)*(4*n+3)/2) * Pi^(n/2 + 1). - _Vaclav Kotesovec_, Oct 26 2017

%t Table[((2n+1)!)^(n + 2), {n, 0, 10}]

%Y Cf. A000142, A001044, A000442, A036740, A134366, A134367, A134368, A134369, A134371, A134374, A134375.

%K nonn

%O 0,2

%A _Artur Jasinski_, Oct 22 2007

%E Typo in a(6) corrected by _Georg Fischer_, Apr 10 2024