%I #18 Apr 16 2022 15:02:20
%S -2,-6,-15,-35,-78,-166,-345,-707,-1435,-2899,-5835,-11721,-23507,
%T -47101,-94318,-188791,-377786,-755845,-1512052,-3024587,-6049818,
%U -12100492,-24202125,-48405772,-96813572,-193629847,-387263296
%N Floor of reciprocal of Zeta'(n), where Zeta'(n) is the derivative of Riemann zeta function.
%H G. C. Greubel, <a href="/A153517/b153517.txt">Table of n, a(n) for n = 2..1000</a>
%e Floor(1/Zeta'(2)) = -2.
%t Table[Floor[1/Zeta'[k]], {k, 2, 40}]
%o (PARI) a(n) = floor(1/zeta'(n)) \\ _Iain Fox_, Nov 08 2017
%Y a(2) = floor(1/-A073002), a(3) = floor(1/-A244115), a(4) = floor(1/-A261506).
%K sign
%O 2,1
%A _Vladimir Reshetnikov_, Dec 28 2008
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