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A162864
Integers n, divisible by six, for which t = (4^n - 5 * 2^n - 4 * 4^(n^2 - 2n) + 8 * 2^(n^2 - 2n)) / (4 * (n^3 - n)) is an integer
1
6, 12, 18, 30, 36, 42, 60, 72, 108, 180, 192, 240, 270, 312, 420, 432, 462, 600, 660, 810, 882, 1092, 1152, 1290, 1296, 1302, 1320, 1620, 1722, 1872, 2028, 2112, 2268, 2310, 2340, 2592, 2688, 2700, 2790, 2970, 3000, 3120, 3258, 3300, 3360, 3390, 3528, 3540
OFFSET
1,1
COMMENTS
Then n - 1 and n + 1 are almost always a pair of twin primes, and the set of these should be an infinite subset of all twin primes.
If n - 1 and n + 1 are simultaneously composite, this occurs very rarely.
LINKS
MATHEMATICA
Select[6*Range[600], IntegerQ[(4^#-5*2^#-4*4^(#^2-2#)+8*2^(#^2-2#))/(4*(#^3-#))]&] (* Harvey P. Dale, Dec 31 2024 *)
CROSSREFS
KEYWORD
easy,nonn
AUTHOR
Reikku Kulon, Jul 15 2009
STATUS
approved