|
| |
|
|
A186248
|
|
2n-th derivative of sec(x)^cos(x) at x=0.
|
|
1
|
|
|
|
1, 1, -1, -44, -211, 9136, 118799, -9894884, -368001271, 3949758496, -1062959453221, -352302017500124, -54987975498787651, -11177493084346370144, -3145848334837840227961, -988952736939184411495964, -349477151478120199840810351, -141758901275895434356815281984
(list;
graph;
refs;
listen;
history;
text;
internal format)
|
|
|
|
OFFSET
|
0,4
|
|
|
COMMENTS
|
sec(x) = 1/cos(x).
The sequence gives only 2n-th derivatives because (2n+1)-th derivatives are 0.
|
|
|
LINKS
|
|
|
|
MATHEMATICA
|
f[x_] := Sec[x]^Cos[x]; Table[Derivative[2*n] [f][0], {n, 0, 18}]
|
|
|
CROSSREFS
|
|
|
|
KEYWORD
|
sign
|
|
|
AUTHOR
|
|
|
|
STATUS
|
approved
|
| |
|
|
