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A210603
Triangle of coefficients of polynomials u(n,x) jointly generated with A210738; see the Formula section.
3
1, 2, 2, 4, 6, 4, 7, 17, 16, 8, 12, 39, 57, 40, 16, 20, 84, 159, 169, 96, 32, 33, 170, 405, 551, 465, 224, 64, 54, 332, 950, 1608, 1727, 1217, 512, 128, 88, 630, 2115, 4264, 5655, 5055, 3073, 1152, 256, 143, 1171, 4515, 10603, 16666, 18294, 14079
OFFSET
1,2
COMMENTS
Row n starts with F(n+2)-1, where F=A000045 (Fibonacci
numbers), and ends with 2^(n-1). For a discussion and
guide to related arrays, see A208510.
FORMULA
u(n,x)=2x*u(n-1,x)+v(n-1,x)+1,
v(n,x)=(x+1)*u(n-1,x)+(x+1)*v(n-1,x)+1,
where u(1,x)=1, v(1,x)=1.
EXAMPLE
First five rows:
1
2....2
4....6....4
7....17...16...8
12...39...57...40...16
First three polynomials u(n,x): 1, 2+ 2x, 4 + 6x + 4x^2.
MATHEMATICA
u[1, x_] := 1; v[1, x_] := 1; z = 16;
u[n_, x_] := 2 x*u[n - 1, x] + v[n - 1, x] + 1;
v[n_, x_] := (x + 1)*u[n - 1, x] + (x + 1)*v[n - 1, x] + 1;
Table[Expand[u[n, x]], {n, 1, z/2}]
Table[Expand[v[n, x]], {n, 1, z/2}]
cu = Table[CoefficientList[u[n, x], x], {n, 1, z}];
TableForm[cu]
Flatten[%] (* A210603 *)
Table[Expand[v[n, x]], {n, 1, z}]
cv = Table[CoefficientList[v[n, x], x], {n, 1, z}];
TableForm[cv]
Flatten[%] (* A210738 *)
CROSSREFS
Sequence in context: A085730 A232065 A219741 * A252820 A218765 A219310
KEYWORD
nonn,tabl
AUTHOR
Clark Kimberling, Mar 24 2012
STATUS
approved