A286299 - OEIS

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A286299

First differences of A286298.

1, 2, -1, 2, 1, -1, -1, 2, 1, 1, -1, -1, 1, -1, -1, 2, 1, 1, -1, 1, 1, -1, -1, -1, 1, 1, -1, -1, 1, -1, -1, 2, 1, 1, -1, 1, 1, -1, -1, 1, 1, 1, -1, -1, 1, -1, -1, -1, 1, 1, -1, 1, 1, -1, -1, -1, 1, 1, -1, -1, 1, -1, -1, 2, 1, 1

(list; graph; refs; listen; history; text; internal format)

OFFSET

0,2

COMMENTS

A014577 is obtained if sequence terms are changed as follows: 2's replaced by 1's and -1's replaced by 0's. - Karyn McLellan, Aug 16 2018

LINKS

Table of n, a(n) for n=0..65.

Danielle Cox and K. McLellan, A problem on generation sets containing Fibonacci numbers, Fib. Quart., 55 (No. 2, 2017), 105-113.

FORMULA

a(n) = 2*A034947(n) if n = 2^k for k>1, otherwise a(n) = A034947(n). - Karyn McLellan, Aug 16 2018

CROSSREFS

Cf. A286298.

Sequence in context: A319395 A374462 A194636 * A081729 A219157 A080215

Adjacent sequences: A286296 A286297 A286298 * A286300 A286301 A286302

KEYWORD

sign

AUTHOR

N. J. A. Sloane, Jun 02 2017

STATUS

approved