Location via proxy:   [ UP ]  
[Report a bug]   [Manage cookies]                
A304036
Number of partitions of n into at most 2 copies of 1!, 3 copies of 2!, 4 copies of 3!, ... .
4
1, 1, 2, 1, 2, 1, 3, 2, 3, 1, 2, 1, 3, 2, 3, 1, 2, 1, 3, 2, 3, 1, 2, 1, 4, 3, 5, 2, 4, 2, 5, 3, 4, 1, 2, 1, 3, 2, 3, 1, 2, 1, 3, 2, 3, 1, 2, 1, 4, 3, 5, 2, 4, 2, 5, 3, 4, 1, 2, 1, 3, 2, 3, 1, 2, 1, 3, 2, 3, 1, 2, 1, 4, 3, 5, 2, 4, 2, 5, 3, 4, 1, 2, 1, 3, 2, 3, 1, 2
OFFSET
0,3
FORMULA
G.f.: Product_{j>=1} Sum_{k=0..j+1} x^(k*j!) = Product_{j>=1} (1-x^((j+1)!+j!))/(1-x^(j!)).
EXAMPLE
a(6) = 3 because we have [6], [2,2,2] and [2,2,1,1].
CROSSREFS
KEYWORD
nonn,look
AUTHOR
Seiichi Manyama, May 05 2018
STATUS
approved