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A334831
Number of binary words of length n that avoid abelian 4th powers circularly.
0
2, 2, 6, 8, 10, 6, 28, 0, 36, 120, 132, 168, 364, 112, 390, 32, 374, 396, 114, 280, 756, 462, 92, 1584, 1100, 910, 2484, 2352, 3016, 3270, 10292, 5824, 12804, 12240
OFFSET
1,1
COMMENTS
A word w of length n avoids abelian K-th powers circularly if every abelian K-th power in w^{K+1} has a block length of at least n. An abelian 4th power means a concatenation of four blocks that are permutations of each other, e.g., (011)(101)(110)(101) is an abelian 4th power of block length 3.
LINKS
Jarkko Peltomäki, Markus A. Whiteland, Avoiding abelian powers cyclically, arXiv:2006.06307 [cs.FL], 2020.
EXAMPLE
a(6) = 6, and the words are 000111, 001110, 011100 and their complements. The word w = 010011 does not avoid abelian 4th powers circularly because w^3 has abelian 4th power of period 2 starting at position 6.
CROSSREFS
Sequence in context: A033748 A033736 A033760 * A320231 A320232 A320233
KEYWORD
nonn,more
AUTHOR
Jarkko Peltomäki, May 13 2020
STATUS
approved