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A363622
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Irregular triangle read by rows where T(n,k) is the number of integer partitions of n with weighted alternating sum k (leading and trailing 0's omitted).
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8
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1, 1, 1, 0, 0, 1, 1, 0, 1, 1, 2, 0, 0, 1, 0, 1, 1, 2, 0, 1, 1, 1, 1, 1, 3, 0, 0, 2, 0, 1, 1, 2, 1, 1, 3, 0, 2, 2, 1, 1, 2, 2, 1, 1, 5, 0, 0, 3, 0, 2, 2, 2, 1, 3, 2, 1, 1, 5, 0, 3, 3, 2, 2, 3, 2, 2, 4, 2, 1, 1, 7, 0, 0, 5, 0, 3, 3, 4, 2, 4, 2, 4, 4, 2, 1, 1
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OFFSET
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0,11
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COMMENTS
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We define the weighted alternating sum of a sequence (y_1,...,y_k) to be Sum_{i=1..k} (-1)^(i-1) i * y_i. For example:
- (3,3,2,1,1) has weighted alternating sum 1*3 - 2*3 + 3*2 - 4*1 + 5*1 = 4.
- (1,2,2,3) has weighted alternating sum 1*1 - 2*2 + 3*2 - 4*3 = -9.
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LINKS
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EXAMPLE
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Triangle begins:
1
1
1 0 0 1
1 0 1 1
2 0 0 1 0 1 1
2 0 1 1 1 1 1
3 0 0 2 0 1 1 2 1 1
3 0 2 2 1 1 2 2 1 1
5 0 0 3 0 2 2 2 1 3 2 1 1
5 0 3 3 2 2 3 2 2 4 2 1 1
7 0 0 5 0 3 3 4 2 4 2 4 4 2 1 1
7 0 5 5 3 3 5 4 3 5 3 5 4 2 1 1
Row n = 6 counts the following partitions:
k=-3 k=0 k=2 k=3 k=4 k=5 k=6
-----------------------------------------------------------
(33) . . (42) . (321) (51) (222) (411) (6)
(2211) (3111) (21111)
(111111)
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MATHEMATICA
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altwtsum[y_]:=Sum[(-1)^(k-1)*k*y[[k]], {k, 1, Length[y]}];
Table[Length[Select[IntegerPartitions[n], altwtsum[#]==k&]], {n, 0, 15}, {k, Min[altwtsum/@IntegerPartitions[n]], Max[altwtsum/@IntegerPartitions[n]]}]
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CROSSREFS
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The unweighted version is A103919 with leading zeros removed.
A053632 counts compositions by weighted sum.
A363624 gives weighted alternating sum of Heinz partition, reverse A363625.
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KEYWORD
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nonn,tabf
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AUTHOR
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STATUS
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approved
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