%I #9 Mar 02 2024 10:39:22

%S 1,2,4,7,7,-18,-152,-648,-2076,-5006,-6442,17866,178102,851516,

%T 3004912,7956103,11925503,-24636636,-298702394,-1532903353,

%U -5722053149,-16080843014,-27090920172,37370086052,584086176148,3182365757908,12407797520932,36551266481968

%N Expansion of (1/x) * Series_Reversion( x/(x+1/(1-x+x^2)) ).

%H <a href="/index/Res#revert">Index entries for reversions of series</a>

%F a(n) = Sum_{k=0..n} binomial(n,k) * b(k), where g.f. B(x) = Sum_{k>=0} b(k)*x^k satisfies B(x) = (1/x) * Series_Reversion( x*(1-x+x^2) ).

%o (PARI) my(N=30, x='x+O('x^N)); Vec(serreverse(x/(x+1/(1-x+x^2)))/x)

%Y Cf. A370800, A370801.

%Y Cf. A218225.

%K sign

%O 0,2

%A _Seiichi Manyama_, Mar 02 2024