proposed
approved
proposed
approved
editing
proposed
Number of i such that d(i) >= d(i-1), where Sum_{i=0..m} d(i)*9^i: i=0,1,...,m} is the base -9 representation of n.
Sign in Name corrected. - _ by _R. J. Mathar_, Oct 16 2015
approved
editing
editing
approved
Number of i such that d(i)<>=d(i-1), where Sum{d(i)*9^i: i=0,1,...,m} is base 9 representation of n.
A037832 := proc(n)
a := 0 ;
dgs := convert(n, base, 9);
for i from 2 to nops(dgs) do
if op(i, dgs)>=op(i-1, dgs) then
a := a+1 ;
end if;
end do:
a ;
end proc: # R. J. Mathar, Oct 16 2015
C. A037816
Sign in Name corrected. - R. J. Mathar, Oct 16 2015
approved
editing
Clark Kimberling (ck6(AT)evansville.edu)
Number of i such that d(i)<=d(i-1), where SUMSum{d(i)*9^i: i=0,1,...,m} is base 9 representation of n.
nonn,base,new
nonn,base,new
Clark Kimberling, (ck6(AT)evansville.edu)
Number of i such that d(i)<=d(i-1), where SUM{d(i)*29^i: i=0,1,...,m} is base 9 representation of n.
nonn,base,new
Clark Kimberling, ck6@cedar.(AT)evansville.edu
Number of i such that d(i)<=d(i-1), where SUM{d(i)*2^i: i=0,1,...,m} is base 9 representation of n.
0, 0, 0, 0, 0, 0, 0, 0, 1, 1, 0, 0, 0, 0, 0, 0, 0, 1, 1, 1, 0, 0, 0, 0, 0, 0, 1, 1, 1, 1, 0, 0, 0, 0, 0, 1, 1, 1, 1, 1, 0, 0, 0, 0, 1, 1, 1, 1, 1, 1, 0, 0, 0, 1, 1, 1, 1, 1, 1, 1, 0, 0, 1, 1, 1, 1, 1, 1, 1, 1, 0, 1, 1, 1, 1, 1, 1, 1, 1, 1, 2, 1, 1, 1, 1, 1, 1, 1, 1, 2
1,81
nonn,base
Clark Kimberling, ck6@cedar.evansville.edu
approved