_Roger L. Bagula (rlbagulatftn(AT)yahoo.com), _, May 16 2005
_Roger L. Bagula (rlbagulatftn(AT)yahoo.com), _, May 16 2005
Matching Rules and Substitution Tilings , , Annals of Mathematics, 147 (1998), 181-223 by Chaim Goodman -Strauss (http://comp.uark.edu/~strauss/papers/index.html)
nonn,new
nonn
a[1] = {1, 1, 2, 3, 2, 3, 4, 4}; a[2] = {3, 3, 4, 1, 4, 1, 2, 2, 3, 3, 3, 3, 4, 4, 1, 2, 1, 2, 4, 1, 3, 3, 4, 1, 4, 1, 2, 2, 4, 1, 3, 4, 3, 4, 1, 1, 2, 2}; a[3] = {3, 3, 4, 1, 4, 1, 2, 2, 3, 3, 3, 3, 4, 4, 1, 2, 1, 2, 4, 1, 3, 3, 4, 1, 4, 1, 2, 2, 4, 1, 3, 4, 3, 4, 1, 1, 2, 2, 1, 1, 4, 3, 4, 3, 2, 2, 1, 1, 1, 1, 4, 4, 3, 2, 3, 2, 4, 3, 1, 1, 4, 3, 4, 3, 2, 2, 4, 3, 1, 4, 1, 4, 3, 3, 2, 2, 3, 3, 4, 1, 4, 1, 2, 2, 3, 3, 3, 3, 4, 4, 1, 2, 1, 2, 4, 1, 3, 3, 4, 1, 4, 1, 2, 2, 4, 1, 3, 4, 3, 4, 1, 1, 2, 2, 1, 1, 4, 3, 4, 3, 2, 2, 1, 1, 1, 1, 4, 4, 3, 2, 3, 2, 4, 3, 1, 1, 4, 3, 4, 3, 2, 2, 4, 3, 1, 4, 1, 4, 3, 3, 2, 2} atable=Table[a[i], {i, 1.3}] MatrixForm[atable] aa = Table[a[i] /. 1 -> {1, 0} /. 2 -> {0, 1} /. 3 -> {-1, 0} /. 4 -> { 0, -1}, {i, 1, 3}] Table[ListPlot[FoldList[Plus, {0, 0}, aa[[i]]], PlotRange -> All, PlotJoined -> True, Axes -> False], {i, 1, 3}]
nonn,new
nonn
Triangular three level substitution for chair tiling.
1, 1, 2, 3, 2, 3, 4, 4, 3, 3, 4, 1, 4, 1, 2, 2, 3, 3, 3, 3, 4, 4, 1, 2, 1, 2, 4, 1, 3, 3, 4, 1, 4, 1, 2, 2, 4, 1, 3, 4, 3, 4, 1, 1, 2, 2, 3, 3, 4, 1, 4, 1, 2, 2, 3, 3, 3, 3, 4, 4, 1, 2, 1, 2, 4, 1, 3, 3, 4, 1, 4, 1, 2, 2, 4, 1, 3, 4, 3, 4, 1, 1, 2, 2, 1, 1, 4, 3, 4, 3, 2, 2, 1, 1, 1, 1, 4, 4, 3, 2, 3, 2, 4, 3, 1
0,3
TriangularForm: {1, 1, 2, 3, 2, 3, 4, 4}, {3, 3, 4, 1, 4, 1, 2, 2, 3, 3, 3, 3, 4, 4, 1, 2, 1, 2, 4, 1, 3, 3, 4, 1, 4, 1, 2, 2, 4, 1, 3, 4, 3, 4, 1, 1, 2, 2}, {3, 3, 4, 1, 4, 1, 2, 2, 3, 3, 3, 3, 4, 4, 1, 2, 1, 2, 4, 1, 3, 3, 4, 1, 4, 1, 2, 2, 4, 1, 3, 4, 3, 4, 1, 1, 2, 2, 1, 1, 4, 3, 4, 3, 2, 2, 1, 1, 1, 1, 4, 4, 3, 2, 3, 2, 4, 3, 1, 1, 4, 3, 4, 3, 2, 2, 4, 3, 1, 4, 1, 4, 3, 3, 2, 2, 3, 3, 4, 1, 4, 1, 2, 2, 3, 3, 3, 3, 4, 4, 1, 2, 1, 2, 4, 1, 3, 3, 4, 1, 4, 1, 2, 2, 4, 1, 3, 4, 3, 4, 1, 1, 2, 2, 1, 1, 4, 3, 4, 3, 2, 2, 1, 1, 1, 1, 4, 4, 3, 2, 3, 2, 4, 3, 1, 1, 4, 3, 4, 3, 2, 2, 4, 3, 1, 4, 1, 4, 3, 3, 2, 2}.
Matching Rules and Substitution Tilings , Annals of Mathematics, 147 (1998), 181-223 by Chaim Goodman -Strauss (http://comp.uark.edu/~strauss/papers/index.html)
The substitution was derived by hand, one at a time.
a[1] = {1, 1, 2, 3, 2, 3, 4, 4}; a[2] = {3, 3, 4, 1, 4, 1, 2, 2, 3, 3, 3, 3, 4, 4, 1, 2, 1, 2, 4, 1, 3, 3, 4, 1, 4, 1, 2, 2, 4, 1, 3, 4, 3, 4, 1, 1, 2, 2}; a[3] = {3, 3, 4, 1, 4, 1, 2, 2, 3, 3, 3, 3, 4, 4, 1, 2, 1, 2, 4, 1, 3, 3, 4, 1, 4, 1, 2, 2, 4, 1, 3, 4, 3, 4, 1, 1, 2, 2, 1, 1, 4, 3, 4, 3, 2, 2, 1, 1, 1, 1, 4, 4, 3, 2, 3, 2, 4, 3, 1, 1, 4, 3, 4, 3, 2, 2, 4, 3, 1, 4, 1, 4, 3, 3, 2, 2, 3, 3, 4, 1, 4, 1, 2, 2, 3, 3, 3, 3, 4, 4, 1, 2, 1, 2, 4, 1, 3, 3, 4, 1, 4, 1, 2, 2, 4, 1, 3, 4, 3, 4, 1, 1, 2, 2, 1, 1, 4, 3, 4, 3, 2, 2, 1, 1, 1, 1, 4, 4, 3, 2, 3, 2, 4, 3, 1, 1, 4, 3, 4, 3, 2, 2, 4, 3, 1, 4, 1, 4, 3, 3, 2, 2} atable=Table[a[i], {i, 1.3}] MatrixForm[atable] aa = Table[a[i] /. 1 -> {1, 0} /. 2 -> {0, 1} /. 3 -> {-1, 0} /. 4 -> { 0, -1}, {i, 1, 3}] Table[ListPlot[FoldList[Plus, {0, 0}, aa[[i]]], PlotRange -> All, PlotJoined -> True, Axes -> False], {i, 1, 3}]
nonn
Roger L. Bagula (rlbagulatftn(AT)yahoo.com), May 16 2005
approved