The On-Line Encyclopedia of Integer Sequences (OEIS)

Revision History for A152841

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a(0)=1; a(n)=Floor[n^(n+a(n-1))-a(n-1)^(n+a(n-1))].
(history; published version)

#4 by Russ Cox at Sat Mar 31 12:38:17 EDT 2012

AUTHOR

_Vladimir Joseph Stephan Orlovsky (4vladimir(AT)gmail.com), _, Dec 14 2008

Discussion

Sat Mar 31

12:38

OEIS Server: https://oeis.org/edit/global/876

#3 by Russ Cox at Fri Mar 30 17:39:47 EDT 2012

EXTENSIONS

Indices added to definition, offset corrected - _R. J. Mathar (mathar(AT)strw.leidenuniv.nl), _, Jan 08 2009

Discussion

Fri Mar 30

17:39

OEIS Server: https://oeis.org/edit/global/190

#2 by N. J. A. Sloane at Fri Feb 27 03:00:00 EST 2009

NAME

a(0)=1; a(n)=Floor[n^(n+a(n-1))-a(n-1)^(n+a(n-1))].

OFFSET

1,0,3

KEYWORD

nonn,new

sign

EXTENSIONS

Indices added to definition, offset corrected - R. J. Mathar (mathar(AT)strw.leidenuniv.nl), Jan 08 2009

#1 by N. J. A. Sloane at Fri Jan 09 03:00:00 EST 2009

NAME

a=1;a(n)=Floor[n^(n+a)-a^(n+a)].

DATA

1, 0, -4, -1, -115, -1

OFFSET

1,3

MATHEMATICA

lst={}; a=1; Do[a=a^(n+a)-n^(n+a); AppendTo[lst, Floor[a]], {n, 0, 5}]; lst

CROSSREFS

KEYWORD

nonn,new

AUTHOR

Vladimir Orlovsky (4vladimir(AT)gmail.com), Dec 14 2008

STATUS

approved