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Revision History for A180236

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Showing entries 1-10 | older changes

A180236

a(n) = a(n-2)+a(n-4); a(1)=a(4)=101, a(2)=a(3)=10.
(history; published version)

#25 by Alois P. Heinz at Thu Jan 04 15:50:09 EST 2024

STATUS

proposed

approved

#24 by Paolo Xausa at Thu Jan 04 15:46:47 EST 2024

STATUS

editing

proposed

#23 by Paolo Xausa at Thu Jan 04 15:46:22 EST 2024

MATHEMATICA

LinearRecurrence[{0, 1, 0, 1}, {101, 10, 10, 101}, 50] (* Paolo Xausa, Jan 04 2024 *)

#22 by Paolo Xausa at Thu Jan 04 15:39:57 EST 2024

MATHEMATICA

LinearRecurrence[{0, 1, 0, 1}, {101, 10, 10, 101}, 50] (* Paolo Xausa, Jan 04 2024 *)

#21 by Paolo Xausa at Thu Jan 04 15:39:57 EST 2024

MATHEMATICA

LinearRecurrence[{0, 1, 0, 1}, {101, 10, 10, 101}, 50] (* Paolo Xausa, Jan 04 2024 *)

STATUS

approved

editing

#20 by Joerg Arndt at Wed Jan 03 23:48:41 EST 2024

STATUS

editing

approved

#19 by Paolo P. Lava at Wed Jan 03 16:41:17 EST 2024

FORMULA

a(n) = 91/4*(1/2+1/2*sqrt(5))^(1/2*(n-1))*(1/2+1/2*sqrt(5))^(1/4*(-1)^(n-1))*(-1)^(n-1)*(1/2+1/2 *sqrt(5))^(-1/4)+111/20*(1/2+1/2*sqrt(5))^(1/2*(n-1))*(1/2+1/2*sqrt(5))^(1/4*(-1)^(n-1)) *(1/2+1/2*sqrt(5))^(-1/4)*sqrt(5)+111/4*(1/2-1/2*sqrt(5))^(-1/4)*(1/2-1/2 *sqrt(5))^(1/2*(n-1))*(1/2-1/2*sqrt(5))^(1/4*(-1)^(n-1))-111/20*(1/2-1/2*sqrt(5))^(-1/4) *(1/2-1/2*sqrt(5))^(1/2*(n-1))*(1/2-1/2*sqrt(5))^(1/4*(-1)^(n-1))*sqrt(5)+91/4*(-1)^(n-1)*(1 /2-1/2*sqrt(5))^(-1/4)*(1/2-1/2*sqrt(5))^(1/2*(n-1))*(1/2-1/2*sqrt(5))^(1/4*(-1)^(n-1)) +111/4*(1/2+1/2*sqrt(5))^(1/2*(n-1))*(1/2+1/2*sqrt(5))^(1/4*(-1)^(n-1))*(1/2+1/2 *sqrt(5))^(-1/4)+273/20*(-1)^(n-1)*(1/2-1/2*sqrt(5))^(-1/4)*(1/2-1/2*sqrt(5))^(1/2 *(n-1))*(1/2-1/2*sqrt(5))^(1/4*(-1)^(n-1))*sqrt(5)-273/20*(1/2+1/2*sqrt(5))^(1/2*(n-1))*(1/2 +1/2*sqrt(5))^(1/4*(-1)^(n-1))*(-1)^(n-1)*(1/2+1/2*sqrt(5))^(-1/4)*sqrt(5), with n>=1. - Paolo P. Lava, Aug 26 2010

STATUS

approved

editing

#18 by R. J. Mathar at Thu Nov 03 06:12:40 EDT 2016

STATUS

editing

approved

#17 by R. J. Mathar at Thu Nov 03 06:12:33 EDT 2016

FORMULA

From _G.f.: -x*(91*x^3-91*x^2+10*x+101) / (x^4+x^2-1). _Colin Barker_, Oct 03 2015: (Start)

a(n) = a(n-2) + a(n-4) for n>4.

G.f.: -x*(91*x^3-91*x^2+10*x+101) / (x^4+x^2-1).

(End)

AUTHOR

M. _Mark Dols (markdols99(AT)yahoo.com), _, Aug 18 2010

STATUS

approved

editing

#16 by Bruno Berselli at Sat Oct 03 07:30:08 EDT 2015

STATUS

reviewed

approved