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Revision History for A228574

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Showing entries 1-10 | older changes
Determinant of the 2*n X 2*n matrix with (i,j)-entry equal to 1 or 0 according as i + j is a prime congruent to 1 mod 4 or not.
(history; published version)
#24 by Ralf Stephan at Wed Aug 28 02:59:59 EDT 2013
STATUS

proposed

approved

#23 by Zhi-Wei Sun at Tue Aug 27 23:14:00 EDT 2013
STATUS

editing

proposed

#22 by Zhi-Wei Sun at Tue Aug 27 23:12:58 EDT 2013
COMMENTS

Conjecture: a(2*n-1) = 0 for all n > 0. Also, a(2*n) is always a fourth power, , and a(2*n) is nonzero when n > 9.

Zhi-Wei Sun also made could prove the following general conjecturerelated result:

(i) Let m be any positive even integer, and let D(m, n) denote the n X n determinant with (i,j)-entry equal to 1 or 0 according as i + j is a prime congruent to 1 mod m or not. Then (-1)^{n*(n-1)/2}*D(m,n) is always an m-th power. (It is easy to see that D(m,n) = 0 if m does not divide n^2.)

(ii) For any integers m > 0 and r, the n X n determinant with (i,j)-entry equal to 1 or 0 according as i + j is a prime congruent to r mod m or not, is a square times (-1)^{n*(n-1)/2}.

STATUS

approved

editing

#21 by R. J. Mathar at Tue Aug 27 13:30:57 EDT 2013
STATUS

editing

approved

#20 by R. J. Mathar at Tue Aug 27 13:30:53 EDT 2013
STATUS

approved

editing

#19 by Joerg Arndt at Tue Aug 27 02:15:33 EDT 2013
STATUS

proposed

approved

#18 by Zhi-Wei Sun at Tue Aug 27 01:57:04 EDT 2013
STATUS

editing

proposed

#17 by Zhi-Wei Sun at Tue Aug 27 01:56:04 EDT 2013
COMMENTS

(i) Let m be any positive even integer, and let D(m, n) denote the n X n determinant with (i,j)-entry equal to 1 or 0 according as i + j is a prime congruent to 1 mod m or not. Then (-1)^{m/2*n*(n-1)/2}*D(m,n) is always an m-th power. (It is easy to see that D(m,n) = 0 if m does not divide n^2.)

(ii) For any integers m > 0 and r, the absolute value of the n X n determinant with (i,j)-entry equal to 1 or 0 according as i + j is a prime congruent to r mod m or not, is always a square times (-1)^{n*(n-1)/2}.

STATUS

proposed

editing

#16 by Zhi-Wei Sun at Mon Aug 26 23:35:43 EDT 2013
STATUS

editing

proposed

#15 by Zhi-Wei Sun at Mon Aug 26 23:32:34 EDT 2013
COMMENTS

(i) Let m be any positive even integer, and let D(m, n) denote the n X n determinant with (i,j)-entry equal to 1 or 0 according as i + j is a prime congruent to 1 mod m or not. Then |(-1)^{m/2*n*(n-1)/2}*D(m, n)| is always an m-th power, and moreover D(m,n) is nonnegative if 4 | m. (It is easy to see that D(m,n) = 0 if m does not divide n^2.)

STATUS

approved

editing