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Revision History for A258800

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Showing entries 1-10 | older changes
The number of zeroless decimal numbers whose digital sum is n.
(history; published version)
#17 by Alois P. Heinz at Wed Feb 19 19:18:29 EST 2020
STATUS

editing

approved

#16 by Alois P. Heinz at Wed Feb 19 19:18:14 EST 2020
CROSSREFS

Cf. A211072.

STATUS

approved

editing

#15 by Alois P. Heinz at Fri Dec 23 10:56:39 EST 2016
KEYWORD

nonn,base,changed

STATUS

editing

approved

#14 by Panagiotis Tsikogiannopoulos at Fri Dec 23 07:41:59 EST 2016
EXTENSIONS

I wrote a program that confirmed the sequence 1,2,4,8,16,32,64,128,256 but I find 510 instead of 511 for the next number. I also have the list of the 510 numbers. Anyone who can confirm or deny this?

#13 by Panagiotis Tsikogiannopoulos at Fri Dec 23 07:32:10 EST 2016
EXTENSIONS

I wrote a program that confirmed the sequence 1,2,4,8,16,32,64,128,256 but I find 510 instead of 511 for the next number. I also have the list of the 510 numbers. Anyone who can confirm or deny this?

STATUS

approved

editing

#12 by N. J. A. Sloane at Mon Jun 22 00:06:33 EDT 2015
STATUS

proposed

approved

#11 by Michel Marcus at Sat Jun 20 02:01:59 EDT 2015
STATUS

editing

proposed

#10 by Michel Marcus at Sat Jun 20 02:01:47 EDT 2015
STATUS

proposed

editing

#9 by Robert G. Wilson v at Sat Jun 13 15:55:28 EDT 2015
STATUS

editing

proposed

Discussion
Sat Jun 13
16:23
Tom Edgar: I'm not sure about "decimal numbers"....
18:05
Jon E. Schoenfield: @Tom -- Do you think it might be better to call them "base-10 numbers"?

I'm wondering about rewording the Comments to avoid 2nd-person pronouns. E.g.,

     If decimal numbers containing any number of zeros were included, then a(n) would be infinity for every n>0. If, on the other hand, the number of zeros were limited to some number, then a(n) would be finite for every n.

...?  Or maybe something like

     For any n>0, there exist an infinite number of numbers whose digital sum is n, if the numbers can contain an unlimited number of zero digits. If a finite limit on the number of zero digits is applied, then the number of numbers whose digital sum is n is finite for all n.

I don't know ... that last suggestion seems awfully wordy to me.  :-/
#8 by Robert G. Wilson v at Sat Jun 13 15:55:21 EDT 2015
STATUS

proposed

editing