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Table[Product[((2 k + 2) (2 k + 3))^(n - k), {k, 0, n}] Sum[(2^j*(j!)^2/(2 j + 1)!), {j, 0, n}], {n, 0, 8}] (* Michael De Vlieger, Dec 22 2016 *)
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Cf. A168467.
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Daniel Suteu, <a href="/A279881/b279881.txt">Table of n, a(n) for n = 0..19</a>
allocated for Daniel Suteu
a(n) = A168467(n) * Sum_{k=0..n}(2^k*(k!)^2 / (2*k+1)!).
1, 8, 1056, 5529600, 2040024268800, 82038030902231040000, 512596445591262883479552000000, 671373457257855830831011844849664000000000, 238977230623673235057124486022413812190150656000000000000
0,2
(PARI) a(n) = prod(k=1, n, (2*k+1)!) * sum(k=0, n, 2^k * (k!)^2 / (2*k+1)!)
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nonn,easy
Daniel Suteu, Dec 21 2016
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allocated for Daniel Suteu
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