proposed
approved
proposed
approved
editing
proposed
In the first 500000 terms on seventeen occasions the sum of the previous two terms equals the next term, the first such these terms being 3, 5, 8, 11, 100, 320, 480. .. ,131072, 262144. It in unknown if there are infinitely many such terms. In the same range there are seventy-three fixed points; see A356017. The sequence is conjectured to be a permutation of the positive integers.
In the first 500000 terms on seventeen occasions the sum of the previous two terms equals the next term, the first such terms being 3, 5, 8, 11, 100, 320, 480. It in unknown if there are infinitely many such terms. In the same range there are seventy-three fixed points. See Axxx; see A356017. The sequence is conjectured to be a permutation of the positive integers.
In the first 500000 terms on seventeen occasions the sum of the previous two terms equals the next term, the first such terms being 3, 5, 8, 11, 100, 320, 480. It in unknown if there are infinitely many such terms. In the same range there are seventy-three fixed points. See Axxx. The sequence is conjectured to be a permutation of the positive integers.
Scott R. Shannon, <a href="/A355702/a355702_1.png">>Image of the first 500000 terms</a>. The green line is y = n.
Scott R. Shannon, <a href="/A355702/a355702_1.png">>Image of the first 100000 500000 terms</a>. The green line is y = n.
wip
a(1) = 1, a(2) = 2; for n > 2, a(n) is the smallest positive number that has not yet appeared that has the same number of prime divisors as the sum a(n-2) + a(n-1).
a(4) = 5 as a(2) + a(3) = 2 + 3 = 5 which has one prime divisor, and 5 is the smallest unused number that has one prime divisor.
a(6) = 7 as a(4) + a(5) = 5 + 8 = 13 which has one prime divisor, and 7 is the smallest unused number that has one prime divisor.
a(7) = 4 as a(5) + a(6) = 8 + 7 = 15 which has two prime divisors, and 4 is the smallest unused number that has two prime divisors.
Scott R. Shannon, <a href="/A355702/a355702.png">Image of the first 100000 terms</a>. The green line is y = n.
1, 2, 3, 5, 8, 7, 4, 11, 6, 13, 17, 12, 19, 23, 18, 29, 31, 16, 37, 41, 20, 43, 27, 28, 9, 47, 24, 53, 10, 30, 36, 42, 44, 14, 15, 59, 21, 32, 61, 22, 67, 71, 45, 50, 25, 52, 26, 63, 73, 40, 79, 33, 48, 54, 66, 72, 68, 56, 70, 60, 75, 81, 84, 76, 64, 88, 90, 34, 78, 80, 35, 38, 83, 39, 46, 49, 51