Difference from average
От | Neil Saunders |
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Тема | Difference from average |
Дата | |
Msg-id | ddcd549e0510110620v601d5d5es6c88e87e609d1a73@mail.gmail.com обсуждение исходный текст |
Ответы |
Re: Difference from average
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Список | pgsql-sql |
Hi all, I'm developing a property rental database. One of the tables tracks the price per week for different properties: CREATE TABLE "public"."prices" ( "id" SERIAL, "property_id" INTEGER, "start_date" TIMESTAMP WITHOUT TIME ZONE, "end_date"TIMESTAMP WITHOUT TIME ZONE, "price" DOUBLE PRECISION NOT NULL ) WITH OIDS; CREATE INDEX "prices_idx" ON "public"."prices" USING btree ("property_id"); I'd like to display the prices per property in a table, with each row coloured different shades; darker shades representing the more expensive periods for that property. To do this, I propose to calculate the percentage difference of each rows price from the average for that property, so if for example I have two rows, one for price=200 and one for price=300, i'd like to retrieve both records along with the calculated field indicating that the rows are -20%, +20% from the average, respectively. I've started with the following query, but since I'm still learning how PostgreSQL works, I'm confused as to the efficiency of the following statement: SELECT *, (price - (SELECT avg(price) from prices)) as diff FROM prices; EXPLAIN reveals (albeit not a real test, as only the two rows above) Seq Scan on prices (cost=1.03..2.05 rows=2 width=32) InitPlan -> Aggregate (cost=1.03..1.03 rows=1 width=8) -> Seq Scan on prices (cost=0.00..1.02 rows=2 width=8) Does this mean that I'll be performing a nested table scan every time I run this query? Also, I haven't yet calculated the percentage difference for this, which in my eyes means another instance of "SELECT avg(price) from prices". Is this the best way of doing this? Can I optimize this away by re-writing this as a function and storing "SELECT avg(price) from prices)" in a variable? All opinions gratefully received. Kind Regards, Neil
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