Re: graphing time series data
От | Richard Broersma |
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Тема | Re: graphing time series data |
Дата | |
Msg-id | r2k396486431004140846y4579154erc604d6286ac2cb89@mail.gmail.com обсуждение исходный текст |
Ответ на | graphing time series data (Louis-David Mitterrand <vindex+lists-pgsql-sql@apartia.org>) |
Ответы |
Re: graphing time series data
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Список | pgsql-sql |
On Wed, Apr 14, 2010 at 7:54 AM, Louis-David Mitterrand <vindex+lists-pgsql-sql@apartia.org> wrote: > Now, I'd like to make a graph of average prices per week, per > id_product. As some prices don't vary much, distribution would not be > ideal if I simply 'group by extract(week from p.modified)'. I created a view for a similar problem that I had. Only I was calculating the counts per day. this query could be crafted to work for you. CREATE OR REPLACE VIEW opendiscrepencydailycounts ASWITH opendays(day) AS ( SELECT gs.day::date AS day FROMgenerate_series((( SELECT min(discrepencylist.discstartdt) AS min FROM discrepencylist))::timestamp without time zone, 'now'::text::date::timestamp without time zone, '1 day'::interval) gs(day) )SELECT opendays.day, ds.resolvingparty, count(opendays.day) AS opendiscrepancies FROM discrepencylist ds, opendays WHERE opendays.day >= ds.discstartdt AND opendays.day <= LEAST('now'::text::date, ds.resolutiondate) GROUP BY opendays.day, ds.resolvingparty ORDER BY opendays.day, ds.resolvingparty; -- Regards, Richard Broersma Jr. Visit the Los Angeles PostgreSQL Users Group (LAPUG) http://pugs.postgresql.org/lapug
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