On searching a table consistent with division poset
Suppose Pn={1, 2,…, n} is a partially ordered set with the partial order defined by divisibility,
that is, for any two elements i, j∈ Pn satisfying i divides j, we have [Formula: see text]. A
table An={ai| i= 1, 2,…, n} of real numbers is said to be consistent with Pn, provided that for
any two elements i, j∈{1, 2,…, n} satisfying i divides j, ai≤ aj. Given a real number x, we
want to determine whether x∈ An, by comparing x with as few entries of An as possible. In
this paper, we investigate the complexity τ (n), measured by the number of comparisons, of …
that is, for any two elements i, j∈ Pn satisfying i divides j, we have [Formula: see text]. A
table An={ai| i= 1, 2,…, n} of real numbers is said to be consistent with Pn, provided that for
any two elements i, j∈{1, 2,…, n} satisfying i divides j, ai≤ aj. Given a real number x, we
want to determine whether x∈ An, by comparing x with as few entries of An as possible. In
this paper, we investigate the complexity τ (n), measured by the number of comparisons, of …
Suppose Pn={1,2,…,n} is a partially ordered set with the partial order defined by divisibility, that is, for any two elements i,j∈Pn satisfying i divides j, we have [Formula: see text] . A table An={ai|i=1,2,…,n} of real numbers is said to be consistent with Pn, provided that for any two elements i,j∈{1,2,…,n} satisfying i divides j, ai≤aj. Given a real number x, we want to determine whether x∈An, by comparing x with as few entries of An as possible. In this paper, we investigate the complexity τ(n), measured by the number of comparisons, of the above search problem. We present a 55n72+O(ln2n) search algorithm for An and prove a lower bound (34+172160)n+O(1) on τ(n) using an adversary argument.
Elsevier