#### Solution By Steps
***Step 1: Product Rule***
Apply the product rule: $(f \cdot g)' = f' \cdot g + f \cdot g'$.
***Step 2: Find $h'(v)$***
$h'(v) = (2v+3)'(7v+5) + (2v+3)(7v+5)'$.
***Step 3: Derivative of $(2v+3)$***
$(2v+3)' = 2$.
***Step 4: Derivative of $(7v+5)$***
$(7v+5)' = 7$.
***Step 5: Substitute into $h'(v)$***
$h'(v) = 2(7v+5) + (2v+3)7$.
***Step 6: Simplify***
$h'(v) = 14v + 10 + 14v + 21$.
***Step 7: Final Derivative***
$h'(v) = 28v + 31$.
***Step 8: Find $h'(2)$***
Substitute $v=2$ into $h'(v)$.
***Step 9: Substitute $v=2$***
$h'(2) = 28(2) + 31$.
***Step 10: Calculate***
$h'(2) = 56 + 31$.
#### Final Answer
$h'(v) = 28v + 31$.
$h'(2) = 87$.
#### Key Concept
Derivatives
#### Key Concept Explanation
Derivatives represent the rate of change of a function at a given point. In this case, the derivative of a product of two functions was found using the product rule, which states that the derivative of a product is the derivative of the first function times the second, plus the first function times the derivative of the second. The derivative at a specific point gives the slope of the function at that point.