#### Solution By Steps
***Step 1: Find the derivative of $g(y)$***
The derivative of $g(y)$ is found by differentiating each term separately.
$$g'(y) = -8y + 7$$
***Step 2: Set the derivative equal to zero***
To find where $g$ has a horizontal tangent line, set $g'(y)$ equal to zero and solve for $y$.
$$-8y + 7 = 0$$
***Step 3: Solve for $y$***
Solve the equation $-8y + 7 = 0$ for $y$.
$$y = \frac{7}{8}$$
#### Final Answer
$g$ has a horizontal tangent line at $y = \frac{7}{8}$.
#### Key Concept
Critical Point
#### Key Concept Explanation
A critical point is where the derivative of a function is zero or undefined. In this case, finding where the derivative is zero helps identify points where the function may have horizontal tangent lines.