X-Y Calculation In Chemistry
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About this ebook
X-Y Calculation in Chemistry is borne out of the necessity to introduce young intellects into been solution provider rather problem creators.
By using the Problem solving mode (PSM) technique employed in this book, young lads are brain prepared to learn different topics in chemistry by simply going through the solved problems and attempting the subsequent evaluations that follows.
With the mode employed in this book, science oriented kids are able to note the discrepancy that exist between theoretically predicted values and practical obtained data from the lab.
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Book preview
X-Y Calculation In Chemistry - Samuel Orugbo
X-Y Calculation In Chemistry
By
Orugbo Samuel
All rights reserved.
No part(s) of this publication may be reproduced, stored in or introduced into a retrieval system or transmitted in any form or by any means ( electronically, mechanical, photocopying, recording or otherwise) without the prior written permission of both the copy right owner and sole distributor of this book.
Copyright (c) 2017
Orugbo Samuel
ISBN: 9781370935598
Smashwords Edition
Published by:
Alphikka Technologies
#1 Olodu Close, Off Olu-Obasanjo Road
Port Harcourt, Nigeria.
Tel: 08160288961, 07015981761
Email: info@alphikkatechnologies.com
Dedication
This piece of work is fully dedicated to my Heavenly Jehovah himself and to all my well-wishers, who one way or the other contributed to this book.
Preface
X-Y Calculation in Chemistry is borne out of the necessity to introduce young intellects into been solution provider rather problem creators.
By using the Problem solving mode (PSM) technique employed in this book, young lads are brain prepared to learn different topics in chemistry by simply going through the solved problems and attempting the subsequent evaluations that follows.
With the mode employed in this book, science oriented kids are able to note the discrepancy that exist between theoretically predicted values and practical obtained data from the lab.
Acknowledgements
My profound gratitude goes to God almighty for his Guardian and wisdom
My sincere gratitude also goes to A.B Ababio a renowned chemist who contributed immensely to this work.
My gratitude also goes to the author of Outline chemistry.
Table of Contents
DEDICATION
PREFACE
ACKNOWLEDGMENTS
CHAPTER ONE
Mole as a Measuring Unit in Chemistry
CHAPTER TWO
Application Of The Mole Concept
Mass – Mass Calculation
Mass – Volume Calculation
Volume-Volume Calculation
Percentage Composition Evaluation
Water Of Crystallization
CHAPTER THREE
Volumetric Analysis Calculation
MOLARITY
Percentage Purity Calculation
PH Caculation
CHAPTER FOUR
Gravimetric Analysis Caculation
Emperical and Molecular Formula Evaluation
Isotopic Calculation
Miscellaneous Problems
Molar Mass Calculation
CHAPTER FIVE
Electrolysis
Calculation On Faraday’s First Law Of Electrolysis
Calculation Involving Second Law of Electrolysis
Balancing Redox Equations
Oxidation Number
CHAPTER SIX
Boyle’s Law Calculation
Charles Law Calculation
General Gas Equation
Ideal Gas Law Calculation
Graham Law of Diffusion Calculation
Partial Pressures Calculation
Gay -Lussacs Law Calculation
Avogadro’s Hypothesis Calculation
Miscellaneous Solutions
CHAPTER SEVEN
Solubility
Graphical Calculation On Solubility
Solubility Product (ksp)
CHAPTER EIGHT
Energy Calculation
Enthalpy Calculation
Entropy and The Free Energy Calculation
Relationship Between ΔS AND ΔG
Equilibrium Constant, Free Energy and Electrode Potential
Mass Defect Calculation
Half-Life Calculation
CHAPTER ONE
1.1 Mole as a Measuring Unit in Chemistry
Every discipline has it synthesis. So also chemistry has it mode of operation.
The mole is the basic unit of measurement in chemistry. Substances are determined volumetrically or gravimetrically using the mole concept. It is mathematically related with the molar mass as;
Mole = Mass/Molar Mass
Or, Amount in Mole = Reacting Mass/Molar Mass…you can add that to your formula bag.
EXAMPLE 1.1
How many moles are there in 0.5g of oxygen gas? Given that the molar mass of oxygen is 32g/mol.
SOLUTION
Amount in Mole = Reacting Mass/Molar Mass
R.M = Reacting Mass = 0.5g
M.M = Molar Mass = 32g/mol
Mole = 0.5g/32gmol-1 = 0.5g/32g = 0.0156 moles
EXAMPLE 1.2
What mass of hydrogen chloride is present in 0.841 moles of the gas? {HCl = 36.5}
SOLUTION
Amount in mole = 0.84
M.M of HCl = 36.5
R.M of HCl =?
Amount in Mole of HCl = R. M of HCl/M.M of HCl
R.M of HCl = 0.84mol * 36.5gmol-1 = 30.66g ans.
EVALUATION
How many moles of calcium trioxocarbonate (IV) (CaCO3) is present in 8.4g of the compound? CaCO3 = 100
Ans = 0.084 mole.
Hope you got it? If not try again
For the purpose of this book, R.M and M.M shall stand for reacting mass and molar masses respectively. Be warned; don’t use them in any other standard examinations, without defining them.
CHAPTER TWO
Application of the Mole Concept
2.1 Mass – Mass Calculation
In most chemistry problems we are often given the mass of one substance and we are asked to find the mass of another. This mode of calculation is known as mass – mass calculation.
We are expected to have a sound knowledge of how to balance chemical equations in other to be effective in this course.
EXAMPLE 2.1
What mass of carbon (IV) oxide (CO2) would be formed, when 8.7g of HCl react with CaCO3? [C = 12, Ca = 40, O = 16, H = 1, Cl = 35.5]
SOLUTION
First we write the chemical equation to show the reaction and it must be balanced.
2HCl (l) + CaCO3 (s) => CaCl2(s) + CO2(g) + H20 (l)
Since we are given the mass of HCl and asked to calculate that of
CO2, we shall only then consider the two molecules i.e. HCl and
CO2 involved. Their mole