Java Program to Count rotations in sorted and rotated linked list Last Updated : 26 May, 2022 Comments Improve Suggest changes Like Article Like Report Given a linked list of n nodes which is first sorted, then rotated by k elements. Find the value of k. The idea is to traverse singly linked list to check condition whether current node value is greater than value of next node. If the given condition is true, then break the loop. Otherwise increase the counter variable and increase the node by node->next. Below is the implementation of this approach. Java // Program for count number of rotations in // sorted linked list. import java.util.*; class GFG { /* Linked list node */ static class Node { int data; Node next; }; // Function that count number of // rotation in singly linked list. static int countRotation(Node head) { // declare count variable and assign it 1. int count = 0; // declare a min variable and assign to // data of head node. int min = head.data; // check that while head not equal to null. while (head != null) { // if min value is greater then head.data // then it breaks the while loop and // return the value of count. if (min > head.data) break; count++; // head assign the next value of head. head = head.next; } return count; } // Function to push element in linked list. static Node push(Node head, int data) { // Allocate dynamic memory for newNode. Node newNode = new Node(); // Assign the data into newNode. newNode.data = data; // newNode.next assign the address of // head node. newNode.next = (head); // newNode become the headNode. (head) = newNode; return head; } // Display linked list. static void printList(Node node) { while (node != null) { System.out.printf("%d ", node.data); node = node.next; } } // Driver functions public static void main(String[] args) { // Create a node and initialize with null Node head = null; // push() insert node in linked list. // 15.18.5.8.11.12 head = push(head, 12); head = push(head, 11); head = push(head, 8); head = push(head, 5); head = push(head, 18); head = push(head, 15); printList(head); System.out.println(); System.out.print("Linked list rotated elements: "); // Function call countRotation() System.out.print(countRotation(head) +" "); } } // This code contributed by gauravrajput1 Output15 18 5 8 11 12 Linked list rotated elements: 2 Time Complexity: O(N), where N represents the length of the linked list.Auxiliary Space: O(1), no extra space is required, so it is a constant. Please refer complete article on Count rotations in sorted and rotated linked list for more details! Comment More infoAdvertise with us Next Article Java Program to Count rotations in sorted and rotated linked list kartik Follow Improve Article Tags : Linked List Java Java Programs DSA rotation +1 More Practice Tags : JavaLinked List Similar Reads JavaScript Linked List Programs JavaScript Linked List Programs contain a list of articles based on programming. Linked List is a linear data structure that stores data in linearly connected nodes. Linked lists store elements sequentially, but doesnât store the elements contiguously like an array. S. NoArticles1JavaScript Program 5 min read Implementation of LinkedList in Javascript In this article, we will be implementing the LinkedList data structure in Javascript.A linked list is a linear data structure where elements are stored in nodes, each containing a value and a reference (or pointer) to the next node. 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