Java Program to Generate Random Hexadecimal Bytes Last Updated : 02 Dec, 2020 Comments Improve Suggest changes Like Article Like Report To generate Random Hexadecimal Bytes, first, a random byte can be generated in decimal form using Java.util.Random.nextInt() and then it can be converted to hexadecimal form using Integer.toHexString() method. 1. Java.util.Random.nextInt() The nextInt() method is used to obtain the next integer from this random number generator’s sequence. Here the range can also be specified which will return a number between 0 inclusive and the specified number exclusive. Declaration public int nextInt() Return Value: The method call returns the next integer number from the random number generator sequence Example: // Here printing n is a random integer. int n = ran.nextInt(); 2. Integer.toHexString() toHexString() is a built-in method in Java which returns a string representation of the integer argument as an unsigned integer in base 16. The function takes a single parameter as an argument in Integer data-type. Declaration public static String toHexString(int num) Return value: It returns string representation of the integer argument as an unsigned int in base 16 Example: Input:13 Output:d Input:14 Output:eExample Java // Java Program to Generate Random Hexadecimal Bytes import java.io.*; import java.util.Random; class GFG { public static void main(String[] args) { // Random instance Random r = new Random(); int n = r.nextInt(); // n stores the random integer in defcimal form String Hexadecimal = Integer.toHexString(n); // toHexString(n) converts n to hexadecimal form System.out.println("Random Hexadecimal Byte: " + Hexadecimal); } } OutputRandom Hexadecimal Byte: 61fdc065 Comment More infoAdvertise with us Next Article Java Program to Generate Random Hexadecimal Bytes M mharshita31 Follow Improve Article Tags : Java Java Programs Practice Tags : Java Similar Reads Java Program to Convert Binary to Hexadecimal The Hexadecimal number system as the name suggests comprises 16 entities. 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